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umka21 [38]
3 years ago
7

Brainliest for free pls

Mathematics
2 answers:
Cloud [144]3 years ago
7 0

Answer: t_{n} = 0.45(5)^{n-1}    (b)

Step-by-step explanation:

a_{n} = 5a_{n-1}

if n = 1 , the sequence becomes :

a_{1} = 5a_{0}

And it was given that the first term is 0.45 , therefore a_{0} = 0.45 , then:

a_{1} = 5(0.45) = 2.25

a_{2} = 5 (5)(0.45) = 11.25

a_{3} = 5(11.25)  = 56.25

Therefore, the common ratio will be 11.25/2.25 = 56.25/11.25 = 5

Recall the formula for nth term of a geometric sequence , which is given as

t_{n} = ar^{n-1}

Substituting the value of a and r , we have

t_{n} = 0.45(5)^{n-1} which is the nth term

ziro4ka [17]3 years ago
4 0

Answer:

dont trust me but

Step-by-step explanation:

I think it tis d or b but mostly d

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In 1 minute, Alex can type 44 words. While working on a project, Alex types from 10:00 AM until 1 AM, He takes a break from 1 0:
viktelen [127]

Answer:

39600 words

Step-by-step explanation:

Given data

In 1 minute, Alex can type 44 words

from 10:00 AM until 1 AM= 15 hours

15 hours to minutes= 15*60= 900 minutes

Hence in In 1 minute, Alex can type 44 words

            in  900 minutes he will type x words

cross multiply

x= 900*44

x= 39600 words

Hence he will type 39600 words

4 0
2 years ago
Answer the questions below about the quadratic function.f(x) = -2x² - 4x
Juli2301 [7.4K]

We are given the function below;

f(x)=-2x^2-4x

PART A

We then proceed to find if the function has a minimum or maximum value. To find if the function has a minimum or maximum value. If the x^2 coefficient is positive, the function has a minimum. If it is negative, the function has a maximum.

ANSWER: From the above, we can see that x^2 is negative, hence the function has a maximum

PART B and C

To find the minimum or maximum value, we would plot the graph of the f(x). The graph can be seen below.

From the graph, the black point helps answer part A and part B.

ANSWER: The function's maximum value is f(x)=2.

This is the point where the slope of the graph is equal to zero

ANSWER: The maximum value then occurs at x= -1

We can also solve this by differentiating the function.

\begin{gathered} f(x)=-2x^2-4x \\ f^{\prime}(x)=-4x-4 \\ At\xi maxmum\text{ }f^{\prime}(x)=0 \\ -4x-4=0 \\ -4x=4 \\ x=-\frac{4}{4} \\ x=-1 \\ \therefore\text{The max}imum\text{ value occurs at x=-1} \\ \text{Inserting the value of x into the function, we have} \\ f(x)=-2(-1)^2-4(-1) \\ f(x)=-2+4 \\ f(x)=2 \\ \therefore\text{The function max}imum\text{ value is 2} \end{gathered}

5 0
1 year ago
In each of the following ,make y the subject and hence find the value of y when a=2, b=3 ,and c=4.
zvonat [6]

Part i


\dfrac{2a-7}{6y} = \dfrac{3b-5}{2c}


y = \dfrac{ 2c(2a-7)}{6(3b-5)} = \dfrac{c(2a-7)}{9b-15}


Substituting,

y = \dfrac{4(2(2)-7)}{9(3)-15} = \dfrac{ -12}{12} = -1


Answer: -1


Part ii


I'm not sure that one's typed in correctly but I'll solve it as written.


3-34y + 2a = \dfrac{3b-5}{2c + 1}


34y  = 3+2a-\dfrac{3b-5}{2c + 1}


y = \frac 1 {34}\left(3+2a-\dfrac{3b-5}{2c + 1} \right)


We're not asked to simplify it so I wont. Substituting,


y = \frac 1 {34}\left(3+2(2)-\dfrac{3(3)-5}{2(4) + 1} \right) = \frac 1 {34}(7-4/9) = \dfrac{59}{306}


Answer: 59/306



3 0
3 years ago
in an examination ,80%examines passed in English ,70%in mathematics and 60% in both subject if 45 examines failed in both find t
stiv31 [10]

Answer:

135 and 135

Step-by-step explanation:

The computation is shown below:

The number of examiners who passed in only one subject is as follows

=  n(E) - n(E ∩M) + n(M) - n(E ∩M)

= (80 - 60 + 70 - 60)%

= 30%

Now the number of students who passed in minimum one subject is

n(E∪M) = n(E) + n(M) -  n(E ∩M)

= 80 - + 70 - 60

= 90%

Now the number of students who failed in both subjects is

= 100 - 90%

= 10% of total students

= 45

So total number of students appeared for this 450

So, those who passed only one subject is

= 450 × 30%

= 135

Now the Number of students who failed in mathematics is

= 100% - Passed in Mathematics

= 100% - 70%

= 30% of 450

= 135

4 0
2 years ago
The area of a trapezoid is 60 square inches. One of the bases is 8 inches long. The height is 6 inches long. What is the length
Mashcka [7]

Answer:

12 in

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h(b₁ + b₂ )

where h is the height and b₁, b₂ the parallel bases

Given h = 6, b₁ = 8 and A = 60 , then

\frac{1}{2} × 6 × (8 + b₂ ) = 60 , that is

3(8 + b₂ ) = 60 ( divide both sides by 3 )

8 + b₂ = 20 ( subtract 8 from both sides )

b₂ = 12

The length of the second base is 12 inches

6 0
3 years ago
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