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3 years ago

Simplify the following expression: -6x + 4(-x - 3)

Mathematics

1 answer:

ss7ja [257]3 years ago

3 0

Answer:

$- 10x - 12$

Step-by-step explanation:

$- 6x + 4( - x - 3) \\ - 6x - 4x - 12 \\ - 10x - 12 \\ = - 2(5x + 6)$

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How many times smaller is 2 × 10^-10 than 4 × 10^-5

natta225 [31]

Answer:

200,000

Step-by-step explanation:

To find how many times smaller is smaller number than greater number, divide greater number by smaller number.

Greater number $=4\times 10^{-5}$

Smaller number $=2\times 10^{-10}$

Then

$\dfrac{\text{Greater number}}{\text{Smaller number}}\\ \\=\dfrac{4\times 10^{-5}}{2\times 10^{-10}}\\ \\=\dfrac{4}{2}\times \dfrac{10^{-5}}{10^{-10}}\\ \\=2\times \dfrac{1}{10^{-5}}\\ \\=2\times 10^5\\ \\=2\times 100,000\\ \\=200,000$

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3 years ago

When coin 1 is flipped, it lands on heads with probability .4; when coin 2 is flipped, it lands on heads with probability .7. On

I am Lyosha [343]

Answer:

Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.

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3 years ago

What is the surface area of a sphere with a radius of 19 units?

almond37 [142]

Hope this helps. Please mark brainliest if it did

Answer: 4536.46

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3 years ago

Complete parts (a) through (c) below.

Yuki888 [10]

Answer:

a) $t_{crit}= 1.34$

b) $t_{crit}=-2.539$

c) $t_{crit}=\pm 2.228$

Step-by-step explanation:

Part a

The significance level given is $\alpha=0.1$ and the degrees of freedom are given by:

$df = n-1= 15$

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

$t_{crit}= 1.34$

Part b

The significance level given is $\alpha=0.01$ and the degrees of freedom are given by:

$df = n-1= 20-1=19$

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

$t_{crit}=-2.539$

Part c

The significance level given is $\alpha=0.05$ and $\alpha/2 =0.025$ and the degrees of freedom are given by:

$df = n-1= 11-1=10$

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

$t_{crit}=\pm 2.228$

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3 years ago

According to the bar graph, which teacher gave 16 minutes of homework on Wednesday?

Natasha_Volkova [10]

Ms.Jones gave sixteen minutes of homework

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3 years ago