Answer:
the slope of both lines are the same.
Step-by-step explanation:
Given the following segment of the Quadrilateral EFGH on a coordinate Segment FG is on the line 3x − y = −2,
segment EH is on the 3x − y = −6.
To determine their relationship, we can find the slope of the lines
For line FG: 3x - y = -2
Rewrite in standard form y = mx+c
-y = -3x - 2
Multiply through by-1
y = 3x + 2
Compare
mx = 3x
m = 3
The slope of the line segment FG is 3
For line EH: 3x - y = -6
Rewrite in standard form y = mx+c
-y = -3x - 6
Multiply through by-1
y = 3x + 6
Compare
mx = 3x
m = 3
The slope of the line segment EH is 3
Hence the statement that proves their relationship is that the slope of both lines are the same.
1. 13/4
2.60
3. in 36 mins (I don't know about this one)
4.<
5. 3/8< 2/3< 19/24
Answer:
B.
Step-by-step explanation:
3(4x-2)-30=-6(6-2x)-20
12x-6-30=-36+12x-20
12x-36=12x-56
5
Step-by-step explanation:
AB=CD (Opposite sides of a parallelogram are equal)
11x-13=42
11x=42+13
11x=55
x=55/11
x=5
