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Marrrta [24]
3 years ago
13

Find the surface area of the rectangular prism. 8 yd 4 yd 5 yd Answer: yd? Submit Answer​

Mathematics
1 answer:
Rashid [163]3 years ago
3 0
The area of the circle is 18
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Which expression indicates 10 subtracted from 9n?
lana [24]
(B) it would be 9n-10
6 0
3 years ago
Read 2 more answers
A vendor sells hot dogs and bags of potato chips. A customer buys 4 hot dogs and 2 bags of chips for $9.00. Another customer buy
stiv31 [10]

Answer: hot dog = $1.75

<u>Step-by-step explanation:</u>

Let h represent hot dogs and c represent bags of chips.

Customer 1: 4h + 2c = 9.00  →  3(4h + 2c = 9.00)  →  12h + 6c =  27.00

Customer 2: 5h + 3c = 11.75 → -2(5h + 3c = 11.75)  → <u>-10h - 6c </u>= <u>-23.50</u>

                                                                                       2h        =    3.50

                                                                                   <u>   ÷2        </u>    <u>   ÷2    </u>

                                                                                        h        =    1.75


7 0
4 years ago
Which expression represents the use of the distributive property for (c+4)(-6)
Mars2501 [29]

Answer:

The answer whould be −6c−24

Step-by-step explanation:

hope this help

5 0
4 years ago
Mrs.smith needed 4 inches of red ribbon for every inch of yellow ribbon to make
Anit [1.1K]

Answer:

28 in of red and 7 in. of yellow.

Step-by-step explanation:

Red ribbon: 7 * 4 = 28 in,

Yellow ribbon: 7 * 1 = 7 in.

5 0
4 years ago
A. Find the first and second derivative of the following function in terms of the parameters c1 and c2.
defon

Answer:

Linear second-order differential equation F(x, y, y′, y″) = 0

y¹¹( -3 x⁴ )+ y¹12 x³ - 12 x² y= 0  

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given differential equation

y = c₁x + c₂x⁴  ...(i)

Differentiating equation (i) with respective to 'x', we get

y¹ = c₁(1) +  c₂ ( 4 x³ ) ...(ii)

Differentiating equation (ii) with respective to 'x', we get

y¹¹ =   c₂ ( 12 x² )

C_{2} = \frac{y^{11} }{12 x^{2} } ...(a)

<u><em>Step(ii)</em></u>:-

Substitute (a) in equation (ii)

y^{l} = C_{1} +  (\frac{y^{ll} }{12x^{2} } ) (4 x^{3} )

C_{1} = y^{l} - (\frac{y^{ll} }{12 x^{2} } ) (4 x^{3} ) ...(b)

C_{2} = \frac{y^{11} }{12 x^{2} }

<u><em>Step(iii):</em></u>-

y  = (y^{l} - (\frac{y^{ll} }{12 x^{2} } ) (4 x^{3} ) x + \frac{y^{ll} }{12 x^{2} } x^{4}

12 x² y = (y¹12 x³ - 4 x⁴ y¹¹) + x⁴ y¹¹

x⁴ y¹¹ - 4 x⁴ y¹¹ + y¹12 x³ - 12 x² y= 0

y¹¹( -3 x⁴ )+ y¹12 x³ - 12 x² y= 0

3 0
3 years ago
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