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Usimov [2.4K]
4 years ago
8

Find the values of c and a for which ABCD must be a parallelogram.

Mathematics
1 answer:
k0ka [10]4 years ago
7 0
The answers A. All you have to do is plug the answer for c in and make sure it matches and then move on to plug in the answer for a and make sure they both work.
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Range. ..............
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Does anyone know what the answer to these are
Elden [556K]

Answer:

1) = 10 \frac{2}{5}  =  \frac{52}{5}

2) =  \frac{252}{25}  = 10 \frac{2}{25}

Step-by-step explanation:

6 \frac{4}{5}  + 3 \frac{3}{5}  \\ (6 + 3) + ( \frac{4}{5}  +  \frac{3}{5} ) \\ 9 +  \frac{7}{5}  = 9 + 1 \frac{2}{5}  \\ 9 + 1 +  \frac{2}{5}  = 10 +  \frac{2}{5}

\boxed{\green{= 10 \frac{2}{5}  =  \frac{52}{5}}}

•◇•◇•◇•◇•◇•◇•◇•◇•◇•◇•

2 \frac{4}{5}  \times 9 \frac{2}{5} \\  \frac{14}{5}  \times 9 \times  \frac{2}{5 }

\boxed{\green{ =  \frac{252}{25}  = 10 \frac{2}{25}}}

6 0
3 years ago
Translate the following words into an algebraic expression.
olganol [36]

Answer:

You've learned how to work with variables and how to evaluate algebra expressions, now we are going to translate words into algebraic expressions.

This skill will come in handy when working with word problems or real life situations. Pay close attention to the "key words" that represent mathematical operations.

You are probably very used to translating words into numerical expressions. Think about this...

We are used to seeing the words, plus, sum, difference, minus, product ...

The good news is that these very same words that we use to write numerical expressions are going to be used to write algebra expressions.

The difference between a numerical expression and an algebra expression is that we will be using variables when writing an algebraic expression. Instead of "8 plus 9" (with two given numbers), you would see, "a number plus 9".

We don't know exactly "what number", so we would use a variable to indicate that it can be any number.

Key words for each operation are indicated in bold. This will help you to easily translate the expression.

As, you can see from the red, bold words, the key words for addition are: sum, more than, plus, increase, add, older than.

Please also remember that addition is commutative; therefore, you can reverse the digits and you will end up with the same answer.

Now, let's take a look at the key words for subtraction.

5 0
3 years ago
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PLEASE HELP!!! 100 POINTS!
arlik [135]

Answer:

  x = 0; y = -6; z = 1

Step-by-step explanation:

You want to find the solution to the system of equations ...

  • 9x+y-3z=-9
  • 10x-y+2z=8
  • -10x-y+4z=10

<h3>Solution</h3>

This set of equations is conveniently solved using the matrix row-reduction features of a scientific or graphing calculator, spreadsheet, or any of a number of apps or on-line calculators.

The attachment shows the solution to be ...

  (x, y, z) = (0, -6, 1)

__

<em>Additional comment</em>

Solving a system of three or more equations "by hand" often can be done by an ad hoc process. It can be done in systematic fashion using Gauss-Jordan reduction techniques, but that often gets messy. Similarly, Cramer's Rule can be used, but that math tends to involve more arithmetic operations than are really necessary.

Adding the first equation to the other two eliminates the y-variable and reduces the system to two equations in two unknowns.

  (9x +y -3z) +(10x -y +2z) = (-9) +(8) . . . . adding [1] and [2]

  19x -z = -1 . . . . simplified

  (9x +y -3z) +(-10x -y +4z) = (-9) +(10) . . . . adding [1] and [3]

  -x +z = 1 . . . . simplified

At this point, we could graph the two equations, or we can proceed algebraically.

Adding these two equations gives ...

  (19x -z) +(-x +z) = (-1) +(1)

  18x = 0   ⇒   x = 0

Using the second of the reduced equations, we find ...

 -x +z = 1

  0 +z = 1   ⇒   z = 1

And using the second of the original equations, gives us ...

  10(0) -y +2(1) = 8

  -y = 6 . . . . . subtract 2

  y = -6 . . . . multiply by -1

Then the solution is (x, y, z) = (0, -6, 1), as above.

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1 year ago
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