1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zepler [3.9K]
1 year ago
11

PLEASE HELP!!! 100 POINTS!

Mathematics
1 answer:
arlik [135]1 year ago
6 0

Answer:

  x = 0; y = -6; z = 1

Step-by-step explanation:

You want to find the solution to the system of equations ...

  • 9x+y-3z=-9
  • 10x-y+2z=8
  • -10x-y+4z=10

<h3>Solution</h3>

This set of equations is conveniently solved using the matrix row-reduction features of a scientific or graphing calculator, spreadsheet, or any of a number of apps or on-line calculators.

The attachment shows the solution to be ...

  (x, y, z) = (0, -6, 1)

__

<em>Additional comment</em>

Solving a system of three or more equations "by hand" often can be done by an ad hoc process. It can be done in systematic fashion using Gauss-Jordan reduction techniques, but that often gets messy. Similarly, Cramer's Rule can be used, but that math tends to involve more arithmetic operations than are really necessary.

Adding the first equation to the other two eliminates the y-variable and reduces the system to two equations in two unknowns.

  (9x +y -3z) +(10x -y +2z) = (-9) +(8) . . . . adding [1] and [2]

  19x -z = -1 . . . . simplified

  (9x +y -3z) +(-10x -y +4z) = (-9) +(10) . . . . adding [1] and [3]

  -x +z = 1 . . . . simplified

At this point, we could graph the two equations, or we can proceed algebraically.

Adding these two equations gives ...

  (19x -z) +(-x +z) = (-1) +(1)

  18x = 0   ⇒   x = 0

Using the second of the reduced equations, we find ...

 -x +z = 1

  0 +z = 1   ⇒   z = 1

And using the second of the original equations, gives us ...

  10(0) -y +2(1) = 8

  -y = 6 . . . . . subtract 2

  y = -6 . . . . multiply by -1

Then the solution is (x, y, z) = (0, -6, 1), as above.

You might be interested in
What does this mean
liraira [26]

Answer:

If you mean the flag it is just to mark the question if you have trouble with it so you can remember to go back and check

Step-by-step explanation:

5 0
3 years ago
HELP PLS <br> Comparing irrational numbers with calculator<br><br> Compare.
julia-pushkina [17]

Answer:

3 2/3 is greater

Step-by-step explanation:

3 2/3 is 3.6666 while √11 is 3.32

6 0
3 years ago
What is the value of x?<br><br> Enter your answer in the box.<br><br> x =
qaws [65]

Answer:

Step-by-step explanation: its yo mama :)

7 0
2 years ago
14. Lara bought gift cards to give as gifts. She bought some $20 movie
lubasha [3.4K]

Answer:

21

Step-by-step explanation:

The x intercept is represented by the coordinate (x,0) on x axis.

So, to find the x intercept ,we need to equate y=0 in the equation 20x+70y=420

=> 20x+ 70*0=420

=> x=420/20 =21.

x intercept is (21,0).

7 0
3 years ago
Read 2 more answers
Which of these is a unit of density?<br> Please help.
katen-ka-za [31]

Answer:

I think is C.

Step-by-step explanation:

Hope it's help you ❤️❤️❤️❤️❤️❤️❤️

7 0
3 years ago
Read 2 more answers
Other questions:
  • 2767545 to the nearest ten
    5·2 answers
  • Serena has 3 necklaces, 6 pairs of earrings, and 4 bracelets in her jewelry box. How many different combinations of a necklace,
    7·2 answers
  • In the parallelogram, &lt;1=3x+15 and &lt;3=7x-5. Find the measure of &lt;2.
    15·1 answer
  • Rob cuts a 15 foot wire into 8 equal pieces about how long is each piece
    11·2 answers
  • Is 225/15/3 equal to 225/(15/3)?
    15·2 answers
  • There are 120 Calories in a 34-cup serving of cereal. How many Calories are there in 6 cups of cereal? Enter your answer in the
    8·1 answer
  • F(x) = 20 - x What is the y intercept
    12·1 answer
  • Find the area of the triangle
    15·1 answer
  • Somebody help please
    8·2 answers
  • PLEASE SOLVE THIS :(<br>​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!