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3 years ago

Translate the following words into an algebraic expression.

Mathematics

2 answers:

olganol [36]3 years ago

5 0

Answer:

You've learned how to work with variables and how to evaluate algebra expressions, now we are going to translate words into algebraic expressions.

This skill will come in handy when working with word problems or real life situations. Pay close attention to the "key words" that represent mathematical operations.

You are probably very used to translating words into numerical expressions. Think about this...

We are used to seeing the words, plus, sum, difference, minus, product ...

The good news is that these very same words that we use to write numerical expressions are going to be used to write algebra expressions.

The difference between a numerical expression and an algebra expression is that we will be using variables when writing an algebraic expression. Instead of "8 plus 9" (with two given numbers), you would see, "a number plus 9".

We don't know exactly "what number", so we would use a variable to indicate that it can be any number.

Key words for each operation are indicated in bold. This will help you to easily translate the expression.

As, you can see from the red, bold words, the key words for addition are: sum, more than, plus, increase, add, older than.

Please also remember that addition is commutative; therefore, you can reverse the digits and you will end up with the same answer.

Now, let's take a look at the key words for subtraction.

11Alexandr11 [23.1K]3 years ago

3 0

Answer:3a-5 = 4x+6

Step-by-step explanation:

let the number be a

3a-5 = 4x+6

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antiseptic1488 [7]

Answer:

1. 14

2. 2.75

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4. 6.5

Step-by-step explanation:

1. You just make a dot plot and count the amount of dots there are.

2. You go to your dot plot and see the smallest amount and you get your answer.

3. Same thing as the smallest amount, except you just have to find the greatest amount.

4. You just find which number appears the most on the dot plot, and bam you got your answer.

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3 years ago

A pile of sand is in the shape of a cone. The diameter of the sand pile is 18 feet and the height is 10 feet.

Mnenie [13.5K]

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8 0

3 years ago

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Difference between 6 and -11

zheka24 [161]

The difference between 6 and -11 is 17
because 6 - (-11) = 17
hope it helps
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3 0

3 years ago

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Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3

babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

$3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3$

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable $z$ first.

Step 1: She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

$(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9$

Now, adding this to equation 1 will cancel out z terms.

$12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4$

Now, she need to make one more equation in $x\ and \ y$ .

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

$(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21$

Now, adding this to equation 2 will not cancel out z terms.

$-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20$

So, she makes mistake in step 2 as the $z$ terms are not being cancelled.

6 0

4 years ago

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I need help on this.

mihalych1998 [28]

To start, we know that an isosceles trapezoid means that the length of P to Q is equal to the length of S to R. Therefore, taking that P is at (0,0), we can say that the distance formula from P to Q is equal to the distance formula from R to S. Our formulas are then $\sqrt{(a-0)^2+(b-0)^2} = \sqrt{(g-c)^2+(b-0)^2}$ if we take that g is the x value for R and b is the y value for R, seeing that Q and R are on the same Y value. Therefore, if we square both sides, we figure out that a²=(g-c)² and a=√(g-c)², so a is either equal to g-c or c-g. As the x value of R is clearly lower than the X value of S, and a is positive, we can take that a=c-g. Thus, because we want to solve for g, or the x value of R, we can add g to both sides to get g+a=c. Then, we can subtract a from both sides to get g=c-a, so you can put a as your answer.

Feel free to ask further questions, and Happy Holidays!

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4 years ago

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