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Sauron [17]
3 years ago
8

Economist Friedrich Hayek argued that ______ can serve as signals in an economy.

Social Studies
2 answers:
arsen [322]3 years ago
8 0
I think the correct answer from the choices listed above is option D. Economist Friedrich Hayek argued that prices can serve as signals in an economy. The prices can tell whether economy is in a good state or not. <span>Most of Hayek’s work from the 1920s through the 1930s was in the Austrian theory of </span>business cycles<span>, capital theory, and monetary theory. </span>
aev [14]3 years ago
5 0

D) Prices.

Economist Friedrich Hayek argued that (prices) can serve as signals in an economy.

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Why should humans allow nature to take its course or why not?
pav-90 [236]
Humans shouldn’t fidget with the course of nature, because it leads to more and more problems.
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3 years ago
Can someone pls help answer true or false
KIM [24]

Answer:

1. true

2. true

3. true

4. false

5. true

6. true

Explanation:

4 0
3 years ago
Why did Christianity appeal to many Romans? Give a detailed response
maksim [4K]

There are at least three reasons why historians might conclude that Christianity appealed more to many Romans than the old Roman religion did.  We must remember that these are ideas that historians propose and not necessarily those that religious people would accept.  Actual Romans might have said they preferred Christianity because God spoke to their hearts and told them it was true.  Historians have to be more cynical and look for worldly causes for religious belief.

One reason that Romans might have liked Christianity is because its god cared about people.  Roman religion was based on transactions.  If people performed certain actions, the gods would perform other actions in return.  It was like buying something on Amazon.  By contrast, in Christianity, God loves all people regardless of what they do or believe.  God hopes that people will do the right thing and will punish them if they do wrong, but he loves them as individuals even when they do bad things.  Historians say that Romans might have liked this idea because it fed their emotional need to feel that they were valuable and worth caring about.

A second factor in Christianity’s popularity might have been its moral code.  Roman religion really did not say much if anything about how people should act in their daily lives.  The gods did not care how people acted towards one another.  The Christian god, on the other hand, handed down a strict set of rules about how people were to behave.  This might have made people like Christianity because it made them feel that they had instructions about how to live their lives.

Finally, historians emphasize Christianity’s inclusive nature.  The Roman world was very unequal.  There were a few elites, a group of people who were well-off, and many, many poor people and slaves.  The Roman religion did not give any of the people of the lower classes a sense that they were valuable.  This is where Christianity was so different.  It taught that all people are equal in the eyes of God.  Historians believe that this would have made many people like the idea of Christianity because it gave them hope that god cared about them regardless of their status and that they, the “meek” would one day inherit the earth.

Historians suggest all of these as reasons why people in Roman times might have been attracted to Christianity.

3 0
3 years ago
Read 2 more answers
Why did the professional dog walker go out of business math worksheet answers?
Gelneren [198K]
Why Did the Professional Dog Walker ao Out of business, math worksheet Answers:

Q1. sin27°   = x/8

Solution:

We have to solve for x, therefore, we will rearrange the given equation for x.

We get,
x = 8 × sin27°

Using the calculator,

sin27° = 0.45

Now substitute the value of sin27° into the main equation.

we get,
x = 8 × 0.45
x = 3.63 (rounded to the nearest hundredth)


Q2. tan 18°  = n / 75

Solution:
We have to solve for n, therefore, we will rearrange the given equation for n.
We get,
n = 75 × tan 18°
Using the calculator,
tan 18° = 0.32
Now substitute the value of tan 18° into the main equation.
we get,
x = 75 × 0.32
x = 24.37 (rounded to the nearest hundredth)

Q3. sin40°  = 4 / a

Solution: We have to solve for a, therefore, we will rearrange the given equation for a.
We get,
a = 4 ÷ sin40°
Using the calculator,
sin40° = 0.64
Now substitute the value of sin40° into the main equation.
we get,
a = 4 ÷ 0.64
a = 6.25 (rounded to the nearest hundredth)

Q4. cos5°   = 92 / y

Solution: We have to solve for y, therefore, we will rearrange the given equation for y.
We get,
y = 92 ÷ cos5°
Using the calculator,
Cos5° = 0.99
Now substitute the value of cos5° into the main equation.
we get,
y = 92 ÷ 0.99
y = 92.92 (rounded to the nearest hundredth)

Q5:
Given the shape attached, therefore, using the triangle given, we have:
Angle of elevation = 35°
length of Opposite side to the angle = x
Length of Hypoteneus = 12
Calculations:
Using the SOH CAH TOA rules:
SOH stands for SineФ = Opposite ÷ Hypotenuse.

CAH stands for CosineФ = Adjacent ÷ Hypotenuse.

TOA stands for TangentФ = Opposite ÷ Adjacent.

Hence,

               SineФ = Opposite ÷ Hypotenuse

Substituting the values:

               Sine35° = x ÷ 12

               0.5735  = x ÷ 12

                          x = 0.5735 × 12

                          x = 6.88 (rounded to the nearest hundredth)

Q6: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 54°
length of the adjacent side to the angle = x
Length of Hypoteneus = 30
Calculations:
Using the SOH CAH TOA rules:

Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Cos54° = x ÷ 30

               0.5877  = x ÷ 30

                          x = 0.5877 × 30

                          x = 17.63 (rounded to the nearest hundredth)

Q7: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 22°
length of the adjacent side to the angle = 85
length of the opposite side to the angle = x
Calculations:

Using the SOH CAH TOA rules:

Hence,

               TangentФ = Opposite ÷ Adjacent

Substituting the values:

               tan22° = x ÷ 85

              0.4040 = x ÷ 85

                          x = 0.4040 × 85

                          x = 34.34 (rounded to the nearest hundredth)

Q8: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 16°
length of the opposite side to the angle = x
Length of Hypoteneus = 14
Calculations:
Using the SOH CAH TOA rules:
Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Sine16° = x ÷ 14

               0.2756  = x ÷ 14

                          x = 0.2756 × 14

                          x = 3.86 (rounded to the nearest hundredth)

Q9: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 65°
length of the adjacent side to the angle = 9
length of the opposite side to the angle = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

               TangentФ = Opposite ÷ Adjacent

Substituting the values:

               tan65° = x ÷ 9

               2.1445 = x ÷ 9

                          x = 2.1445 × 9

                          x = 19.30 (rounded to the nearest hundredth)

Q10: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 51°
length of the adjacent side to the angle = x
Length of Hypoteneus = 70
Calculations:
Using the SOH CAH TOA rules:
Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Cos51° = x ÷ 70

              0.6293  = x ÷ 70

                          x = 0.6293 × 70

                          x = 44.05 (rounded to the nearest hundredth)

Q11: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 36°
length of the opposite side to the angle = 15
Length of Hypoteneus = x
Calculations:
Using the SOH CAH TOA rules:
Hence,

               CosineФ = Adjacent ÷ Hypotenuse

Substituting the values:

               Sine36° = 15 ÷ x

               0.5877  = 15 ÷ x

                          x = 15 ÷ 0.5877

                          x = 25.52 (rounded to the nearest hundredth)

Q12: Given the shape attached, therefore, using the triangle given, we have:

Angle of elevation = 60°
length of the adjacent side to the angle = x
length of the opposite side to the angle = 100

Calculations:
Using the SOH CAH TOA rules:

Hence,

               TangentФ = Opposite ÷ Adjacent

Substituting the values:

               tan65° = 100 ÷ x

               2.1445 = 100 ÷ x

                          x = 100 ÷ 2.1445

                          x = 46.63 (rounded to the nearest hundredth)

Q13: When a 25-ft ladder is leaned against a wall, it makes a 72° with the ground. How high up on wall does the ladder reach?

Solution: Given the shape attached, therefore, using the triangle given, we have:

The angle of elevation from the ground = 72°
length of the wall opposite to the angle = X
Length of ladder (Hypoteneus) = 25 feet

Calculations:
Using the SOH CAH TOA rules:
Hence,

               SineФ = Opposite ÷ Hypotenuse

Substituting the values:

               Sine72° = x ÷ 25

               0.9510  = x ÷ 25

                          x = 25 ÷ 0.9510

                          x = 23.77 (rounded to the nearest hundredth)


ANSWERS TO QUESTION 14 AND  15 ARE ATTACHED

7 0
3 years ago
Why did the U.S. fear communism during the Cold War? (Below - Write 3 sentences)
tatiyna

Answer:

The US feared communism during the cold war because they thought that it would put limits on their freedoms. The US felt that if their rights were taken away communism would make it to where they would never be able to get out of control of communism. And it would make it where the US would never be able to gain back any power they had in the first place, or go above their power level.

Explanation:

(I hope this made sense)

7 0
3 years ago
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