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2 years ago

What explicit formula matches the arithmetic sequence -2, 1, 4, 7, 10, ...?

Mathematics

1 answer:

Ray Of Light [21]2 years ago

5 0

$a_1=-2\\
d=3\\
a_n=a_1+(n-1)d=-2+(n-1)\cdot3=-2+3n-3=3n-5$

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The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between x(height) and y(arm span) is sho

abruzzese [7]

Answer:

27.385 cm longer would we expect Mike's arm span to be than George's.

Step-by-step explanation:

We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:

y= 4.5x + 0.977 x

where y= arm span

and x= height

Given:

Mike's height=x = 175 cm

so Mike's arm span= y= 4.5 x + 0.977 x

= 4.5* (175) + 0.977* (175)

= 787.5 + 170.975

= 958.475 cm

George's height = x = 170 cm

so George's arm span= y= 4.5 x + 0.977 x

= 4.5* (170) + 0.977* (170)

= 765 + 166.09

= 931.09 cm

Mike's arm span longer than George's = Mike's arm span - George's arm span

= 958.475 - 931.09

= 27.385 cm.

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tangare [24]

Answer:

Step-by-step explanation:

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An employee pays what percentage for FICA?

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Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

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2 years ago