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2 years ago

What numerical expression represents the phrase: the difference of 4 cubed 25

Mathematics

2 answers:

vredina [299]2 years ago

7 0

I need point sorry I need point sorry I need point sorry I need point sorry

Eddi Din [679]2 years ago

4 0

Answer:

ita A hope it helps

Step-by-step explanation:

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What are verbs? Example

Eva8 [605]

Answer:

Hi! Hope this helps!

Step-by-step explanation:

A verb is used to describe actions.

Example: I JUMPED over the rock. In this sentence the verb is JUMPED

8 0

2 years ago

Read 2 more answers

(2.75 x 107) + (1.23 x 108) simplify

Thepotemich [5.8K]

Answer:

427.09

Step-by-step explanation:

(2.75 x 107) + (1.23 x 108)

294.25 + 132.84 = 427.09

6 0

2 years ago

The points (3, 9) and (–3, –9) are plotted on the coordinate plane using the equation y = a • x.

marysya [2.9K]

The answer would be a=3

7 0

2 years ago

12 belongs to which set(s) of numbers?o Natural Numbers, Whole Numbers, and Integers onlyNatural Numbers and Whole Numbers onlyo

erastova [34]

Integers are written without no fractional components so 12 is an integer .

Natural numbers are positive numbers just like the number we count. 12 is a natural number.

Rational numbers

3 0

11 months ago

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago