What is the domain of the function represented by this graph?

Help please Asap!!! Find the missing fraction ?blank??+1/3=3/4

Vaselesa [24]

Answer:

5/12

Step-by-step explanation:

You have to make it a common denomator and then subract until equeal.

8 0

2 years ago

Read 2 more answers

4✓6 × 3✓6 multiply and simplify show work

mafiozo [28]

Answer:

3

√

2

Explanation:

First put change the words into an equation:

√

3

×

√

6

Now you can multiply them together as you would normally multiply:

√

3

×

√

6

=

√

18

Now let's prime factor 18 and see if there are any squares that we can take out of it to simplify. All we have to see is if there are 2 numbers that are the same:

18

/ \

6

3

/ \

2

3

As you can see, we have a square:

3

×

3

=

9

So take

√

9

out of

√

18

. You should have:

√

9

√

2

But since

√

9

=

3

we can simplify further to make:

√

9

√

2

→

3

√

2

Step-by-step explanation:

3 0

2 years ago

110$ for 16ft find the unit rate

Neporo4naja [7]

Answer:

6.875 dollars per feet

Step-by-step explanation:

110/16

6.875

8 0

2 years ago

I really need help with this Triangle problem

hjlf

Answer:

30

Step-by-step explanation:

pythagoras theorem

x

${x}^{2}$

$=225 \times 2 + 225 \times 2 \\$

=900

x=30

3 0

2 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

2 years ago