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2 years ago

6

F(x) = -x(2nd power) + 4 when x = 3

1 answer:

Pepsi [2]2 years ago

5 0

F(x) = -x² + 4
f(3) = -3² + 4
f(3) = -9 +4
f(3) = -5

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Find the difference (7a-6b+7) - (8a-2)

olga nikolaevna [1]

Hey there!

Let's set up our expression:

(7a-6b+7)-(8a-2)

In order to simplify, we can use that subtraction sign and distribute it, using the distributive property. We have:

7a-6b+7-8a+2

Notice how it's plus two, because a negative times a negative two is a positive two. Now, it's a matter of finding the like terms and adding or subtracting them. These like terms can either have no variable, or have different coefficients but the same variable. That means our like terms are the 7a and -8a, and the 7 and 2. There's no like term for the 6b. That means we have:

(7a-8a) - 6b + (7+2) =

-a - 6b + 9

Hope this helps!

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2 years ago

Kelly joins Powerhouse Gym. The cost is $30 per month and a one-time $100 joining fee. Lisa joins MegaMuscle Gym for $35 per mon

xeze [42]

In 10 months Lisa will have paid the same amount as Kelly, but in month 11 she will have paid more.

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2 years ago

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Simplify this expression.

GalinKa [24]

I believe the answer is C

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3 years ago

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The area of a mirror is 225 Square inches, it's width is

Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

<em><u>Solution:</u></em>

Given that area of mirror is 225 square inches

$width = 13\frac{3}{4} \text{ inches }$

Converting the above mixed fraction we get,

$width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }$

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

$225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36$

Thus length of mirror is 16.36 inches

<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is $\frac{55}{4} = 13.75$ inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

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3 years ago

Need help please cant understand this probplem

klasskru [66]

Answer:

No solution

Step-by-step explanation:

Distribute the right side of the equation.

This will make it 3/8f+1/2=3/8f - 18

And, since 3/8f plus 1/2 will never equal the same thing as 3/8f minus 18, there are no solutions

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2 years ago

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