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3 years ago

Please Help Me!!! 98 Points for Brainliest!!

Mathematics

2 answers:

-Dominant- [34]3 years ago

7 0

Answer:

As x → ± ∞, y → -2 ⇒ y = -2

Step-by-step explanation:

Savatey [412]3 years ago

6 0

vertical asymptote at x = 2 and x = - 2

horizontal asymptote at y = 2

the function → ± ∞ at x = 2 and x = - 2 ⇒ vertical asymptotes

As x → ± ∞, y → -2 ⇒ y = -2 is a horizontal asymptote

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Which of the following is a line segment as shown in the drawing? ED EH DH CD

Nata [24]

Answer:

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Step-by-step explanation:

a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line between its endpoints.

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2 years ago

Read 2 more answers

A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib

fenix001 [56]

Answer: 0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = $\mu=50\times190=9500\text{ pounds}$

Standard deviation of 50 people $=\sigma=40\sqrt{50}=40(7.07106781187)=282.84$

Then , the probability its maximum safe load will be exceeded =

$P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855$

Thus , the probability its maximum safe load will be exceeded = 0.03855

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3 years ago

Which of the following expressions is equivalent to a perfect square?

Liula [17]

Answer:

Step-by-step explanation:

if you do the math you end up with 49 which is a perfect square of 7

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2 years ago

What is the decay factor of the exponential function represented by the table? o w/n who O 02 O 6

Gwar [14]

Answer:

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Step-by-step explanation:

For each term multiply each number to see what value you get, only 1/3 makes sense

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2 years ago

Please help me ASAP!

faust18 [17]

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3 years ago