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3 years ago

Please Help Me!!! 98 Points for Brainliest!!

Mathematics

2 answers:

-Dominant- [34]3 years ago

7 0

Answer:

As x → ± ∞, y → -2 ⇒ y = -2

Step-by-step explanation:

Savatey [412]3 years ago

6 0

vertical asymptote at x = 2 and x = - 2

horizontal asymptote at y = 2

the function → ± ∞ at x = 2 and x = - 2 ⇒ vertical asymptotes

As x → ± ∞, y → -2 ⇒ y = -2 is a horizontal asymptote

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Rápido y fácil, trigonometría. Urgente porfavor

enot [183]

Answer:

The angle $\theta$ measures approximately $28.81^o$

Step-by-step explanation:

Since this problem involves the finding of an angle in a right angle triangle for which we know the opposite side and the adjacent side, the trigonometric function that relates them is the tangent:

$tan(\theta)=\frac{opposite}{adjacent}$

Then, for our case we get a starting equation that reads:

$tan(\theta)=\frac{opposite}{adjacent} \\tan(\theta)=\frac{7.7}{14}$

and for which we need to solve for $\theta$ . Then we use the arctangent function to get the final answer:

$tan(\theta)=\frac{7.7}{14} \\\theta=arctan(\frac{7.7}{14})\\\theta= 28.81^o$

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3 years ago

IF KOBE HAD 8 DUNKS AND LEBRON HAD 10, HOW MANY MORE DUNKS DID LEBRON HAVE THEN KOBE?

pav-90 [236]

Answer:

Step-by-step explanation:

10-8

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3 years ago

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According to the theorem, which statement about parallelogram ABCD is true?

givi [52]

Answer:

The answer is D

Step-by-step explanation:

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2 years ago

What is the simplest form of the expression below?

sineoko [7]

Answer:

(B) cot Theta

Step-by-step explanation:

We want to simplify the expression:

$\dfrac{cot\theta cos\theta}{sin\theta } X\dfrac{tan\theta}{\frac{sin\theta}{cos\theta tan \theta} }$

Now:

$\dfrac{ cos\theta}{sin\theta } =cot\theta\\\dfrac{ sin\theta}{cos\theta }=tan \theta\\$Substituting these into the expression\\\dfrac{cot\theta cos\theta}{sin\theta } X\dfrac{tan\theta}{\frac{sin\theta}{cos\theta tan \theta} }=cot\theta cot\theta X\dfrac{tan\theta}{\frac{tan\theta}{ tan \theta} }\\=cot\theta cot\theta X tan\theta$ (Since cot\theta X tan\theta =1) \\$Therefore our result:\\=cot\theta$

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3 years ago

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