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-Dominant- [34]
3 years ago
5

Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7.

A random sample of 49 students has been selected. The standard error of the mean for this sample is _______. 10.6 9.1 63.7 28.4 The standard deviation of X^bar (or the standard error of the sample mean) is calculated as the positive squareroot of the variance. It is computed as se(X^bar) = sigma/Squareroot n.
Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

Option B) 9.1      

Step-by-step explanation:

We are given the following in the question:

Average score = 490.4

Standard deviation = 63.7

Sample size, n = 49

Formula:

=\dfrac{\sigma}{\sqrt{n}}

Putting values, we get,

Standard error =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{63.7}{\sqrt{49}} = 9.1

Thus, the correct answer is

Option B) 9.1

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Answer:

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Step-by-step explanation:

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\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}The figure below shows that your parabola has its vertex at (5,2).

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