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aleksandr82 [10.1K]
3 years ago
10

PLEASE HELP ASAP 25 POINTS

Mathematics
2 answers:
Lena [83]3 years ago
4 0
The answer to the question is a)
Nookie1986 [14]3 years ago
4 0

Answer is A .


How?

See the horizontal line parallel to x-axis.Now with the help of graph,I can write some points on that horizontal line which are:(0,3),(2,3),(-2,3),etc.Just analyze these points.In these points you can see that y-coordinate is constant and is equal to 3.So the equation of this horizontal line is:

y=3 which is analogous to y<=3(Why not y>=3 because the line limits the value to 3 )

The slanted line can be represented by y>2x-1

Also see this image to know why this slanted line bounds the region y>2x-1





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What is the value of 4x to the third +4x if x is 4
weqwewe [10]
The correct answer of
4{x}^{2}  + 4x
if x=4 is 272.

to solve the equation if x equals 4, you must substitute the x of the 4.
4( {4}^{3} ) + 4(4)
then solve by order of operations.
solve what is inside the parentheses first
4(64) + 4(4)
then do the multiplication of the factors
256 + 16
then the final step, adding, to get the solution of 272
5 0
3 years ago
a farm, in the shape of an isosceles trapezoid, is putting up fences on its diagonals. If 1 fence has sixteen 9 - foot segments,
iragen [17]

Answer:

18

Step-by-step explanation:

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x = 18

3 0
3 years ago
Someone please help me??
lapo4ka [179]
The standard equation of a circle with centre (xc,yc) and radius R is given by

(x-x_c)^2+(y-y_c)^2=R^2

Substituting
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(x-x_c)^2+(y-y_c)^2=R^2
(x-4)^2+(y-(-3))^2=2.5^2
(x-4)^2+(y+3)^2=2.5^2  or
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7 0
3 years ago
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qaws [65]

Answer:

1. coefficient

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Step-by-step explanation:

3 0
3 years ago
Help me please !!!
Nat2105 [25]

Answer:

For 3x^2+4x+4=0

Discriminant= = -32

The solutions are

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= -44

The solutions

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= -36

The solutions

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a= (1-√-1)/3

Step-by-step explanation:

Formula for the discriminant = b²-4ac

let the discriminant be = x for the equations

The solution of the equations

= (-b+√x)/2a and = (-b-√x)/2a

For 3x^2+4x+4=0

Discriminant= 4²-4(3)(4)

Discriminant= 16-48

Discriminant= = -32

The solutions

(-b+√x)/2a =( -4+√-32)/6

(-b+√x)/2a= (-4 +4√-2)/6

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a =( -4-√-32)/6

(-b-√x)/2a= (-4 -4√-2)/6

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= 2²-4(3)(4)

Discriminant= 4-48

Discriminant= -44

The solutions

(-b+√x)/2a =( -2+√-44)/6

(-b+√x)/2a= (-2 +2√-11)/6

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a =( -2-√-44)/6

(-b-√x)/2a= (-2 -2√-11)/6

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= (-6)²-4(9)(2)

Discriminant= 36 -72

Discriminant= -36

The solutions

(-b+√x)/2a =( 6+√-36)/18

(-b+√x)/2a= (6 +6√-1)/18

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a =( 6-√-36)/18

(-b-√x)/2a= (6 -6√-1)/18

(-b-√x)/2a= (1-√-1)/3

6 0
3 years ago
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