Answer:
Step-by-step explanation:




is the rectangular equation of the parameter functions.
also, it is a hyperbola. The condition
limit x from 0 to infinitive
<span>1) y = -f(x) (This is the reflection about the x-axis of the graph y = f(x).) That is for every point (x, y) there is a point (x, -y).
</span><span>2) y = |f(x)| means that the entire graph will be above the x-axis. Why? (The absolute value is always positive, that's why!!)<span> To graph the absolute value graph, graph the function y = f(x). Anything above the x-axis, stays above it, anything below the x-axis is reflected above the x-axis and anything on the x-axis, stays on the x-axis.
</span></span><span>3) y = f(-x) (This is reflection about the y-axis of the graph y = f(x)) For every point on the right of the y-axis, there is a point equidistant to the left of the y-axis. That is for every point (x, y), there is a point (-x, y).
</span><span>4) Reflections about the line y = x is accomplished by interchanging the x and the y-values. Thus for y = f(x) the reflection about the line y = x is accomplished by x = f(y). Thus the reflection about the line y = x for y = x2 is the equation x = y2. </span>

Let's solve ~

[ according to given figure ]




Correct choice is D
The point with the greatest distance to the origin is given by:
B. (-3, 3).
<h3>What is the distance between two points?</h3>
Suppose that we have two points,
and
. The distance between them is given by:

The origin is given by point (0,0), hence the distance of a point (x,y) to the origin is given by:
D = sqrt(x² + y²).
Hence the distances for each point given in the problem are:
- A. Distance = sqrt((-4)² + (-1)²) = sqrt(17).
- B. Distance = sqrt((-3)² + (3)²) = sqrt(18).
- C. Distance = sqrt((4)² + 0²) = sqrt(16).
- D. Distance = sqrt((2)² + 3²) = sqrt(13).
Hence option B has the greatest distance.
More can be learned about the distance between two points at brainly.com/question/18345417
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