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swat32
3 years ago
15

Which equation could represent the relationship shown in the scatter plot?

Mathematics
2 answers:
KonstantinChe [14]3 years ago
8 0
Choice D : look at where you think the line would be if it followed the direction of the data so that about half of the points fell above the line and half below. The two most important things to note are the slope of the line and y intercept.
This is a negative relationship as the line falls as you read it from left to right. That eliminates choice C. Next, it appears the line of best fit would have a y intercept around 10 on the y axis and then fall down and to the right cutting the data. Note that choices A and B have y intercepts that don't make sense for the data. Choice D does have a y intercept of 10 and a negative slope.
svet-max [94.6K]3 years ago
3 0

Answer: D.y=-3/4x+10


Step-by-step explanation:


You might be interested in
Write the equation of the line shown in point slope form (1,2) (3,6)
Kipish [7]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (1, 2) and (3, 6). Substitute:

m=\dfrac{6-2}{3-1}=\dfrac{4}{2}=2\\\\\boxed{y-2=2(x-1)}

7 0
3 years ago
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
Pls hurry !!<br> 8x+2=5x+12 simplified fraction
leonid [27]

Answer: 10/3

Step-by-step explanation: trust me my guy g o o g l e is always correct

8 0
3 years ago
Read 2 more answers
Formula for addition
wolverine [178]

Answer: Click on the cell where you want the result of the calculation to appear. Type = (press the equals key to start writing your formula) Click on the first cell to be added (B2 in this example) Type + (that's the plus sign)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How do I do multi digit multiplication?
Alexus [3.1K]

A web search will turn up numerous videos that are available to answer that question. Often, you may find them more satisfactory than the static explanation of a text answer.

The fundamental idea is that the product is the sum of the products of the parts of the number(s). That is, the distributive property applies.

Here is an example.

... 12 × 34

... = (10 +2)×(30 +4)

... = 10(30 +4) +2(30 +4)

... = 10·30 + 10·4 + 2·30 + 2·4

... = 300 + 40 + 60 + 8

... = 408

_____

Here's an interpretation of what we've just seen that is a little unconventional. The product is the following sum:

... (1·3)×100 + (1·4 + 2·3)×10 + (2·4)×1

If you look at the place values of the digits being multiplied, you see that the multiplier here (×100 or ×10 or ×1) is the product of the place values of the digits involved. That is, when a digit in the 10s place is multiplied by another in the 10s place, their product contributes to the 100s place (10×10) of the result.

One method of multidigit multiplication that is taught is to only write down the partial sums obtained by adding products with the same "place" contribution in the result. That is, the product of 1s place digits (2 and 4 in our example) will go in the 1×1=1s place of the result.

The sum of products of the 10s and 1s place digits (1·4 + 2·3) = 10 will go in the 10×1 = 10s place of the result.

The product of the 10s place digits (1·3) = 3 will go in the 10×10 = 100s place of the result.

If you're good at keeping numbers in your head (gets easier with practice), this method can be faster than other more conventional ways to do it.

For numbers of more digits and/or of different lengths (say a 3-digit by 5-digit number), there are more partial sums, but the idea stays the same. It can be helpful to add leading zeros to the short number to make the numbers the same length.

Here's an example with two 5-digit numbers. Digits are chosen to be different so you can see what is being multiplied at each stage. Pay attention to the pattern being used to select digits to play with.

17986\\03524\\\\=(6\cdot 4)\times 1+(8\cdot 4+6\cdot 2)\times 10+(9\cdot 4+8\cdot 2+6\cdot 5)\times 100\\+(7\cdot 4+9\cdot 2+8\cdot 5+6\cdot 3)\times 1000\\+(1\cdot 4+7\cdot 2+9\cdot 5+8\cdot 3+6\cdot 0)\times 10000\\+(1\cdot 2+7\cdot 5+9\cdot 3+8\cdot 0)\times 10^5\\+(1\cdot 5+7\cdot 3+9\cdot 0)\times 10^6+(1\cdot 3+7\cdot 0)\times 10^7+(1\cdot 0)\times 10^8\\=63,382,664

It can be convenient to write down partial sums vertically aligned with the numbers being multiplied. (Put the sum where its place value indicates it should go.) Here, we have proceeded from right to left, but you can also do it proceeding from left to right. (Of course, the product of anything with zero is zero, so can be skipped or ignored.)

Some find it convenient to write the higher-order digits of a sum on separate lines, vertically aligned according to place value. For example, the partial sums we got in the exercise above were 24, 44, 82, 104, 87, 64, 26, and 3. Those might be written like this ...

\begin{array}{cccccccc}3&6&4&7&4&2&4&4\\2&6&8&0&8&4&2\\&&1\\6&3&3&8&2&6&6&4\end{array}

where the last line in this array is the sum of the rows above, hence the result of the multiplication.

_____

When the numbers have decimal digits, the number of decimal places in the result will be the total of the numbers of decimal places in the numbers being multiplied. For example, 8.31×5.6 has 2+1=3 total decimal digits, so the result will have 3 decimal digits. (It is 46.536.) Sometimes such a multiplication will have a product that ends in zeros. Those zeros are counted when placing the decimal point. (1.2×1.5 = 1.80 with 2 decimal digits.)

3 0
3 years ago
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