Answer:
12:10 or 6:5
Step-by-step explanation:
If 2 more girls join, the ratio will be 12:10 or 6:5.
Answer: P(none of them Europeans play against each other)=
Explanation:
Since there are 8 teams in which 3 are Europeans.
So, remaining 5 teams are not Europeans
We have to take 2 teams to pair up.
And we have a condition that neither of team is European.
So the favourable outcome =
and the total outcomes=
So, by using theprobability formula i.e.
P(E)=
P(getting none of European team play against each other)=
=
=
Answer: 6
Step-by-step explanation:
SOLUTION:
We are to pick from the given tiles the pairs that are associated with each functions.
Note that each of the pairs are of the form (x,y) coordinates.
(1)

The correct tiles for this function with explanation are given as follow;



![\begin{gathered} (0.5,\sqrt[]{6)} \\ y\text{ = }\sqrt[]{6}\text{ when x = 0.5} \\ y=6^x \\ \sqrt[]{6}=6^{0.5} \\ \sqrt[]{6}=6^{\frac{1}{2}} \\ \sqrt[]{6}\text{ = }\sqrt[]{6} \\ \text{Correct} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%280.5%2C%5Csqrt%5B%5D%7B6%29%7D%20%5C%5C%20y%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B6%7D%5Ctext%7B%20when%20x%20%3D%200.5%7D%20%5C%5C%20y%3D6%5Ex%20%5C%5C%20%5Csqrt%5B%5D%7B6%7D%3D6%5E%7B0.5%7D%20%5C%5C%20%5Csqrt%5B%5D%7B6%7D%3D6%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%5C%5C%20%5Csqrt%5B%5D%7B6%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B6%7D%20%5C%5C%20%5Ctext%7BCorrect%7D%20%5Cend%7Bgathered%7D)
For the first function, above tried tiles are the associated ones any other one different from those explained above are not associated with the fuction.
(2)

The correct tiles for this function are given as follow;
![(6,1),\text{ (1, 0), (36 ,2) and (}\sqrt[]{6\text{ }}\text{ , 0.5)}](https://tex.z-dn.net/?f=%286%2C1%29%2C%5Ctext%7B%20%281%2C%200%29%2C%20%2836%20%2C2%29%20and%20%28%7D%5Csqrt%5B%5D%7B6%5Ctext%7B%20%7D%7D%5Ctext%7B%20%2C%200.5%29%7D)
Let me explain or prove two out of the four tiles.

![\begin{gathered} (\sqrt[]{6},\text{ 0.5)} \\ y\text{ = 0.5 when x = }\sqrt[]{6} \\ y=\log _6x \\ 0.5\text{ =}\log _6\sqrt[]{6} \\ \frac{1}{2}=\log _66^{\frac{1}{2}} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\log _66 \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ x 1} \\ \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ } \\ \\ \text{Correct} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%28%5Csqrt%5B%5D%7B6%7D%2C%5Ctext%7B%200.5%29%7D%20%5C%5C%20y%5Ctext%7B%20%3D%200.5%20when%20x%20%3D%20%7D%5Csqrt%5B%5D%7B6%7D%20%5C%5C%20y%3D%5Clog%20_6x%20%5C%5C%200.5%5Ctext%7B%20%3D%7D%5Clog%20_6%5Csqrt%5B%5D%7B6%7D%20%5C%5C%20%5Cfrac%7B1%7D%7B2%7D%3D%5Clog%20_66%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B1%7D%7B2%5Ctext%7B%20%7D%7D%3D%5Ctext%7B%20%7D%5Cfrac%7B1%7D%7B2%7D%5Clog%20_66%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B1%7D%7B2%5Ctext%7B%20%7D%7D%3D%5Ctext%7B%20%7D%5Cfrac%7B1%7D%7B2%7D%5Ctext%7B%20x%201%7D%20%5C%5C%20%20%5C%5C%20%5Cfrac%7B1%7D%7B2%5Ctext%7B%20%7D%7D%3D%5Ctext%7B%20%7D%5Cfrac%7B1%7D%7B2%7D%5Ctext%7B%20%7D%20%5C%5C%20%20%5C%5C%20%5Ctext%7BCorrect%7D%20%5Cend%7Bgathered%7D)
You can also use the approach above to confirm the remaining two.