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WARRIOR [948]
3 years ago
11

Consider a bag of jelly beans that has 30 red, 30 blue, and 30 green jelly beans. a) How many color combinations of 15 beans hav

e at least 6 green beans
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
5 0

Answer:

680

Step-by-step explanation:

Number of red beans = 30

Number of Blue beans = 30

Number of green beans = 30

How many color combinations of 15 beans have at least 6 green beans?

Since at least 6 of the beans must be green,

Then (15 - 6) = 9

Then, the remaining 9 could be either red, blue or green.

Therefore, C(9 + (9 - 1), 3)

C(17, 3) = 17C3

nCr = n! ÷ (n-r)! r!

17C3 = 17! ÷ (17 - 3)! 3!

17C3 = 17! ÷ 14!3!

17C3 = (17 * 16 * 15) / (3 * 2)

17C3 = 4080 / 6

17C3 = 680 ways

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Eight teams are competing in the quarter-finals of a world football championship title. Three out of them are European.
zhuklara [117]

Answer: P(none of them Europeans play against each other)=\frac{5}{14}

Explanation:

Since there are 8 teams in which 3 are Europeans.

So, remaining 5 teams are not Europeans

We have to take 2 teams to pair up.

And we have a condition that neither of team is European.

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So, by using theprobability formula i.e.

P(E)=\frac{\text{No. of favourable outcome}}{\text{Total no. of outcomes}}

P(getting none of European team play against each other)=\frac{\binom{5}{2}}{\binom{8}{3}}

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3 years ago
How many faces does the following shape have?
kow [346]

Answer: 6

Step-by-step explanation:

8 0
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Help would be nice, i’m out of school from covid
Mashcka [7]

SOLUTION:

We are to pick from the given tiles the pairs that are associated with each functions.

Note that each of the pairs are of the form (x,y) coordinates.

(1)

y=6^x

The correct tiles for this function with explanation are given as follow;

\begin{gathered} (1,6)\text{ } \\ y\text{ = 6 when x =1 } \\ y=6^x \\ 6=6^1 \\ \text{Correct} \end{gathered}\begin{gathered} (0,1) \\ y\text{ = 1 when x = 0} \\ y=6^x \\ 1=6^0 \\ \text{Correct} \end{gathered}\begin{gathered} (2,36) \\ y=36\text{ when x = 2} \\ y=6^x \\ 36=6^2 \\ \text{Correct} \end{gathered}\begin{gathered} (0.5,\sqrt[]{6)} \\ y\text{ = }\sqrt[]{6}\text{ when x = 0.5} \\ y=6^x \\ \sqrt[]{6}=6^{0.5} \\ \sqrt[]{6}=6^{\frac{1}{2}} \\ \sqrt[]{6}\text{ = }\sqrt[]{6} \\ \text{Correct} \end{gathered}

For the first function, above tried tiles are the associated ones any other one different from those explained above are not associated with the fuction.

(2)

y=\log _6x

The correct tiles for this function are given as follow;

(6,1),\text{ (1, 0), (36 ,2) and (}\sqrt[]{6\text{ }}\text{ , 0.5)}

Let me explain or prove two out of the four tiles.

\begin{gathered} (6,\text{ 1)} \\ y\text{ = 1 when x =6} \\ y=\log _6x \\ 1=\log _66 \\ \text{Correct} \end{gathered}\begin{gathered} (\sqrt[]{6},\text{ 0.5)} \\ y\text{ = 0.5 when x = }\sqrt[]{6} \\ y=\log _6x \\ 0.5\text{ =}\log _6\sqrt[]{6} \\ \frac{1}{2}=\log _66^{\frac{1}{2}} \\  \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\log _66 \\  \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ x 1} \\  \\ \frac{1}{2\text{ }}=\text{ }\frac{1}{2}\text{ } \\  \\ \text{Correct} \end{gathered}

You can also use the approach above to confirm the remaining two.

5 0
1 year ago
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