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Vinil7 [7]
3 years ago
5

An absentminded professor does not remember which of his 12 keys will open his ocedoor. Suppose he tries them at random and with

replacement. Find the probability that heopens his oce door after three tries.
Mathematics
1 answer:
kipiarov [429]3 years ago
8 0

Answer: 0.0052

Step-by-step explanation:

Total number of times experiment was performed (n)= 12

Probability of the event (that one key out of a total of 12 opens the door) = 1/12 = 0.083

Hence, p = 0.83

q = 1 - p = 11/12 = 0.917

x = 3

Since the experiment was performed n number of times, a binomial probability distribution can defined the experiment.

P(x=r) = nCr ×p^r × q^n-r

P(x=3) = 12C3 × (0.083)⁴ × (0.917)^8

P(x=3) = 220 × (0.083)⁴ × (0.917)^8

P(x=3) = 0.0052

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Twelve years ago, Jane was five times as old as Anne. In three years' time, Anne will be half Jane's
Soloha48 [4]

Answer:

Jane: 37 years old

Anne: 17

Step-by-step explanation:

Jane 12 years ago: 5x

Anne 12 years ago: x

In three years into the future:

Jane: 5x+15

Anne: x+15

CURRENT TIME:

Jane: 5x+12

Anne: x+12

Equation (using 3 years into the future ages): 5x+15=2(x+15)

5x+15=2x+30

(subtract 15 from both sides)

5x=2x+15

3x=15

x=5

Therefore, Jane is 37 years old and Anne is 17 years old.

3 0
3 years ago
Can i have some help i need to find the surface area​
makkiz [27]

Answer:

644ft^2

Step-by-step explanation:

Area of triangle=1/2bh

Area of square=l*l

so we have;

4 triangles with a base of 14ft and height of 16ft and 1 square with l=14ft

AreaTriangle=1/2(14ft)(16ft)=112ft*4=448ft^2

AreaSquare=14ft*14ft=196ft^2

Area Total=448ft+196ft=644ft^2

7 0
3 years ago
If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
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3 0
3 years ago
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What is the common ratio in the following geometric sequence?
sesenic [268]

Answer:

Correct answer:  q = 4

Step-by-step explanation:

Given:

3, 12, 48, 192, .....

First term       b₁ = 3

Second term b₂ = 12

Third term     b₃ = 48

Fourth term   b₄ = 192

Common ratio or quotient is:

q = b₂ / b₁ = b₃ / b₂ = 12 / 3 = 48 / 12 = 4

q = 4

God is with you!!!

7 0
3 years ago
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