H(t)=- 16t^2 +16t+12 zeros of the parabola

Mathematics

1 answer:

igomit [66]3 years ago

8 0

Step-by-step explanation:

h(t) = -16t² + 16t + 12

h(t) = -4(4t² - 4t - 3)

h(t) = -4(2t - 3)(2t + 1)

When h(t) = 0, we have t = 1.5 or t = -0.5.

Hence the zeroes are 1.5 and -0.5.

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