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m_a_m_a [10]
3 years ago
7

One student runs 90,000 millimeters, and another runs 20,000 centimeters

Mathematics
1 answer:
Ratling [72]3 years ago
4 0

Answer:

Second student ran more than the first student.

Student 1=  9,000 cm

Student 2= 20,000 cm

Step-by-step explanation:

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NEED HELP FAST!!!
mina [271]
Remember

we can do anything to an equation as long as we do it to both sides

try to isolate the variable

you have 2 types
x+b=c
x/b=c

fior the first type, minus b from both sides to get
x=c-b

for the second, multiply both sides by b to get rid of the fraction to get
x=cb

also remember that -x times -1=x



b.add 25 to both sides
-a=20
multiply -1
a=-20


c.
-t/8=-4
multiply both sides by 8
-t=-32
mutiply -1
t=32

d. -n/-5=-30
mulitply both sides by -5
-n=150
multiply both sides by -1
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e. multiply both sides by 12
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4 0
3 years ago
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How do you work out pie charts if thewy don't have any numbers on them?
abruzzese [7]
Adding on to the previous, estimate FRACTIONS of the chart, and then figure out the percentage of those fractions
6 0
4 years ago
What is 2/6 using simplest form
scoray [572]
1/3

You’re able to divide both the numerator (2) and denominator (6) by 2
6 0
3 years ago
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t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.
kondaur [170]

Answer:

a) t = 1, b)  t = -2, c) Concave upward: (-\infty, 1). No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}

By factorizing each component, the function is re-arranged as:

f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}

There is no avoidable discontinuities. The only point where tangent line is vertical is t = 1.

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is  horizontal is t = -2.

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}

f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]

f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}

f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}

The only critical point is:

-6\cdot (t+2) = 0

t = -2 (which coincides with the result of point b)

f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]

f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}}  \right]

The value associated with the critical point is:

f''(-2) = \frac{2}{9}

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is (-\infty, 1). There is no absolute maximums and, therefore, there is no interval that is concave downward.

7 0
4 years ago
What is the volume of the triangular prism
nalin [4]

Find the area of the triangle, them multiply by the depth.

Area of triangle = 1/2 x 9 x 8 = 36

Volume = 36 x 9 = 324 cubic centimeters.

3 0
3 years ago
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