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UNO [17]
3 years ago
12

Estimate 36.76 divided by 2.9 using compatible numbers - will give brainliest for correct answer

Mathematics
2 answers:
vekshin13 years ago
8 0

Answer:

12.68 if you are rounding to the hundreths place

Step-by-step explanation:

Kazeer [188]3 years ago
6 0

Answer:

12.68

Step-by-step explanation:

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0.16(a-4)=0.3(2a+4)<br>Solve the Equation
Black_prince [1.1K]
The answer is a= -4.181818
5 0
4 years ago
Please, I really need help-
posledela
<h3>Answer: 48</h3>

=====================================================

Explanation:

Triangle ABC is isosceles because AC = BC.

The angles opposite these congruent sides are angle ABC and angle BAC. These are the base angles.

For any isosceles triangle, the base angles are congruent.

Angle BAC = 69 degrees is given. So angle ABC = 69 as well.

-------------------

The missing angle must add to the two other angles so that all three angles in a triangle add to 180

(angle ABC) + (angle BAC) + (angle BCA) = 180

69 + 69 + (angle BCA) = 180

138 + (angle BCA) = 180

angle BCA = 180-138

angle BCA = 42

-------------------

Angle DCE is congruent to angle BCA because they are vertical angles.

Triangle DCE is a right triangle. The missing angle is 90-(angle BCA) = 90-42 = 48

angle EDC = 48 degrees

6 0
4 years ago
Read 2 more answers
What angles are supplementary to &lt;7
Rzqust [24]

Answer:

173°

Step-by-step explanation:

supplementary angles add up to 180°

hence,180-7=173°

4 0
3 years ago
(08.01)Maggie wants to know how many students in her school enjoy watching sports on TV. She asks all 25 students in her math cl
Elodia [21]
C because the students were not pulled at random

4 0
3 years ago
Read 2 more answers
how to use Lcd in this problem? [a-2. -_1_ =_3_]find Lcd [ a+3 1 a-2]. (a+3)(a+2). multiply all neumerator to (LCD) a-2 - 1= 3 _
san4es73 [151]

It's not entirely clear to me what you're trying to solve, but it looks like the initial equation is

\dfrac{a-2}{a+3} -1 = \dfrac3{a+2}

First convert each term into a fraction with the same (i.e. the least common) denominator. The first term needs to be multiplied by <em>a</em> + 2; the second term by (<em>a</em> + 3) (<em>a</em> + 2); and the third term by <em>a</em> + 3 :

\dfrac{a-2}{a+3}\cdot\dfrac{a+2}{a+2} -1\cdot\dfrac{(a+3)(a+2)}{(a+3)(a+2)} = \dfrac3{a+2}\cdot\dfrac{a+3}{a+3} \\\\ \dfrac{(a-2)(a+2)}{(a+3)(a+2)} - \dfrac{(a+3)(a+2)}{(a+3)(a+2)} = \dfrac{3(a+3)}{(a+3)(a+2)}

Now that everything has the same denominator, we can combine the fractions into one. Move every term to one side and join the numerators:

\dfrac{(a-2)(a+2)-(a+3)(a+2)-3(a+3)}{(a+3)(a+2)} = 0

Simplify the numerator:

\dfrac{(a^2-4)-(a^2+5a+6)-(3a+9)}{(a+3)(a+2)} = 0 \\\\ \dfrac{-8a-19}{(a+3)(a+2)} = 0

If neither <em>a</em> = -3 nor <em>a</em> = -2, we can ignore the denominator:

-8a-19 = 0

Solve for <em>a</em> :

-8a = 19 \\\\ \boxed{a = -\dfrac{19}8}

4 0
3 years ago
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