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3 years ago

Slope 2/7; through (8,0)

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

8 0

Are you looking for the equation of the line? If so do you need point slope or slope intercept form?

prisoha [69]3 years ago

8 0

Y=mx +b
0 = 2/7(8) + b
b = - 16/7

equation

y = 2/7x - 16/7

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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (29pt

Ad libitum [116K]

Answer:

I think its b

Step-by-step explanation:

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3 years ago

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Choose the benchmark that 3-7/12 closest to 3-1/2 2. 3

luda_lava [24]

Answer:

Step-by-step explanation:

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3 years ago

What does the measure of B Equal?

defon

You have two triangles, ADC and ABC.
Sides AD and AB are congruent.
Sides DC and BC are congruent.
Side AC is congruent to itself.
By SSS, triangles ADC and ABC are congruent.

Corresponding parts of congruent triangles are congruent.
That means that angles DAC and BAC are congruent.
Angles DCA and BCA are congruent.

Since m<DAC = 32, then m<BAC = 32
Since m<DCA = 41, then m<BCA = 41.

Now you know the measures of two angles of triangle ABC.
The measures of the interior angles of a triangle add to 180.
You can find the measure of angle B.

m<BAC + m<B + m<BCA = 180

32 + m<B + 41 = 180

m<B + 73 = 180

m<B = 107

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4 years ago

the building on the poster is 36cm tall. is it possible to figure out how tall the building is on the photograph?if its possible

Olenka [21]

No because the stupidity of you can not calculate

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3 years ago

Solve the system by using a matrix equation. --4x - 5y = -5 -6x - 8y = -2

evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

$\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}$

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

$\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}$

Step # 1 : Swap the first and second matrix rows,

$\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}$

Step # 2 : Cancel leading coefficient in row 2 through $R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1$ ,

$\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}$

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

$\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}$

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0

3 years ago