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olya-2409 [2.1K]
3 years ago
7

Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Straight lines.

Since there are more than one lines that can land plane safely, we take one of it,

When, X = 10 and Y = 7, so the equation we get as,

y-7 = m(x-10) + c

lets find slope, that is value of m,

y2-y1/x2-x1 = m

so, 9-7/ 7-10 = 2/-3

so, m= -2/3

so the final Equation is,

=> y-7 =(-2/3)(x-10) +c

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Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2
ololo11 [35]

Answer:

The solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

y=6x-3\\y=x-2

Solving:

Let:

y=6x-3--eq(1)\\y=x-2--eq(2)

Put value of y from equation 2 into equation 1

y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}

Now, put value of x in equation 2 to find value of y

y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}

So, the solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

7 0
3 years ago
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