Since the bucket has already a mass of 2,000 kg, therefore
the maximum mass of gravel would only be:
15,000 kg – 2,000 kg = 13,000 kg gravel
Solving for volume:
volume = 13,000 kg / (1,500 kg / 1 m^3)
volume = 8.67 m^3
<span>Therefore about 8.67 cubic meter of gravel can be safely
loaded by the crane.</span>
There are many ways to work this out. One way could be:
Add up:
1/4 + 1/4 + 1/4 = 3/4
Find 3/4 of 8 so;
8 / 4 = 2
2 x 3 = 6
Find what's remaining:
8 - 6 = 2
So Mr.Greg has sandwiches left.
Hope it helped :)
Answer: " b = 3 ⅕ ; or, write as: 3.2 .
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Given: "A = (1/2) * b * h " ;
↔ A = (b * h) / 2
2A = (b*h) ;
2A/ h = b ;
↔ b = (2A) / h ;
Given A = 48 ; and h = 30 ; Plug in these values; and solve for "b" ;
→ b = (2*48) / 30 ;
= 96/30 ;
= (96÷6) / (30÷6) ;
→ b = 16/5 ; = 3 <span>⅕ ; or, write as: 3.2 .
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(5, -2) because y=(x-5)^2-2 is really y=x^2-10x+23 after you foil then take the derivative which is y'=2x-10 solve for x and you get 5 then put 5 in the original equation and you get -2 so the answer is (5, -2)<span />
