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andrey2020 [161]
3 years ago
9

What are the answers

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0
U should look these up on mathway
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The domain of f(x) is the set of all real values except 7, and the domain of g(x) is the set of all real values except -3. Which
Maurinko [17]

Answer:

The option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>

Step-by-step explanation:

As the domain of f(x) is the set of all real values except 7. So it can be written as follows:

              Domain of f(x) = { x ∈ R | x ≠ 7}

As the domain of g(x) is the set of all real values except -3. So it can be written as follows:

              Domain of g(x) = { x ∈ R | x ≠ -3}

It is a common rule that the domain of a composite function (gºf)(x) will be the set of those input x in the domain of f for which f(x) is in the domain of g.

So, the option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>

Keywords:  domain, composite function

Learn more domain and composite functions from brainly.com/question/2073574

#LearnwithBrainly

3 0
3 years ago
How do I add the fractions <br> 1/4 + 1/7 please help me
kiruha [24]
First, you have to find the LCD. The LCD of 4 and 7 is 28, so you rewrite the fraction:
7/28
4/28

Then you add them.
8 0
3 years ago
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A house cat weighs 9.22 pounds Hercules the liger is the worlds largest cat and weighs 100 times the weight of the house cat how
Tanya [424]

Answer:

922 pounds

Step-by-step explanation:

9.22 x 100 = 922

5 0
3 years ago
Convert 35 mi/h to km/h
notsponge [240]
<span>Convert 35 mi/h to km/h

</span>35  \dfrac{mi}{h}\to  \dfrac{km}{h}\qquad \qquad 1 mi= 1,60934 \\  \\  \\ 35  \dfrac{mi}{h}* \dfrac{1,60934\ km}{1\ mi}= \boxed{  56,3269\dfrac{km}{h} }<span>
</span>
3 0
3 years ago
An expression is shown.
borishaifa [10]

Answer: (14.4 x 8)-4

Step-by-step explanation:

add 2.8 and 11.6 and multiply 8 your answer will be 115.2 but when you subtract it with the four you will get the same thing when you calculate the regular problem.I hope this help

6 0
3 years ago
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