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Gelneren [198K]
3 years ago
8

A light bulb consumes 600 watt-hours per day. How many watt-hours does it consume in 3 days and 18 hours

Mathematics
2 answers:
Harman [31]3 years ago
7 0

Answer:

2250 watt-hours

Step-by-step explanation:

Convert 3 days and 18 hours= 3 days + 3/4 days=3.75 days

1 day a light bulb consumes 600 watt-hours

3.75 days a light bulb consumes 600x3.75 watt-hours

Lelechka [254]3 years ago
3 0

Answer:

2250 watt-hours

Step-by-step explanation:

Okay, so we first need to find out how many watt-hours the light bulb consumes in 1 hours, so we need to divide 600 by 24 hours, which gives us a rate of 25 watt-hours per hour.

So if the light bulb consumes 600 hours per day, and it runs for 3 days, you multiply 600 by 3 to get 1800.

And because we know that it also consumes 25 watt-hours per hour, we multiply 25 and 18 together to get 450 hours.

Finally, you add 1800 and 450 together to get 2250 watt-hours.

Hope this helps :)

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<h3>Answer:</h3>
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<h3>Step-by-step explanation:</h3>

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It can also be used to simplify the product of binomials (or other polynomials).

  (a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2

  (a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering

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For the purposes of calculation, it can be easier to factor out 100:

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Then for x = 0.97

  = 100(1 -0.97) = 100(0.03) = 3

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2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81

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Step-by-step explanation:

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For g(x)=1/2x-11, find x when g(x)=-5
Vesna [10]

Answer:

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<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = 1/2x - 11

g(x) = -5

<u>Step 2: Solve for </u><em><u>x</u></em>

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  2. Isolate <em>x</em> term:              6 = 1/2x
  3. Isolate <em>x</em>:                       12 = x
  4. Rewrite:                        x = 12
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