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Pachacha [2.7K]
3 years ago
8

Benali's has a bag filled with marbles. There are 7 blue marbles and 1 green marble. she reaches into the bag and pulls out a ma

rble. she keeps this marble out of the bag. Then she reaches in again and pull out another marble. What is the probability that she selected a blue marble first and a blue marble second?
Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0
7/8 and 6/7........................i think
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sarabeth is making beaded necklaces to give to five of her friends for homecoming she has 10 ft of elastic string each necklace
babunello [35]

Answer:

Yes, she has enough strong to make necklaces for five friends

Step-by-step explanation:

10 ft= 120 inches

120/20 9=in per necklace= 6

she has enough to make 6 necklaces and she only has to make five so yes

5 0
2 years ago
The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f
Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

h(t)=-16t^{2}+25t+5

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

so

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

h(t)=-16(t^{2}-\frac{25}{16}t)+5

Complete the square

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}

h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}

Rewrite as perfect squares

h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

The vertex is the point (\frac{25}{32},\frac{945}{64})

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}

16(t-\frac{25}{32})^{2}=\frac{945}{64}

(t-\frac{25}{32})^{2}=\frac{945}{1,024}

square root both sides

(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}

t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}

the positive value is

t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec

8 0
3 years ago
Sharon was going through the financial records of her company. The profit earned by the company, p(t), over time t, in years, fo
FromTheMoon [43]
For this case what we must do is find a quadratic function that is already factored.
 This is because in the factored quadratic equations, it is easier to observe the zeros of the function.
 In this case, the zeros of the function represent the time at which the company did not make any profit.
 We have the following equation:
 p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
 We observed that there was no gain in:
 t = 3
 t = 5
 The other roots are discarded because they are negative
 Answer:
 
a.p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
5 0
3 years ago
Work out the value of a and b in the identity.<br> 3ax + 6 - 4(x + b)= 11x + 14
Levart [38]

Answer:

a=5, b=-2

Step-by-step explanation:

If you simplify the equation, you get:

3ax +6 -4x -4b - 11x - 14 = 0 =>

3ax - 15x -4b -8 = 0

group together x's and constants:

(3a-15)x -8 -4b = 0

To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2

5 0
3 years ago
Find the zeros of the function g(x) = x2 - 6x - 16 by factoring. what is the largest zero of the function? enter a number only.
aleksandrvk [35]
(X-8)(x+2) is the factored equation. Ur zeros r -2 and 8. So the largest should be 8?
5 0
3 years ago
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