a. 6, 8, 10, 12, 14
Work:
a_1 = 2(1) + 4
a_1 = 6
a_2 = 2(2) + 4
a_2 = 8
a_3 = 2(3) + 4
a_3 = 10
a_4 = 2(4) + 4
a_4 = 12
a_5 = 2(5) + 4
a_5 = 14
b. 500
Work:
Since the common difference is 2, we can add 2 to each number until we reach the 20th term.
6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 = 500
Ill Say Probably 49 Different Type Of Sums.
Answer:
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Step-by-step explanation:
Step-by-step explanation:
For 1st question
the correct option is
a. 25
For second question
The correct option is
a. 81 / 4
Hope it will help :)
