<h3>Given :-</h3>
<h3>To Find :-</h3>
<h3>Solution :-</h3>
☼︎ <u>Radius of the Circle</u>;
<h3>Using Formula:</h3>

<u>Putting values in the formula;</u>









henceforth, the Radius of a circle is 14 cm ...!!
60-12-18-2-8=20
=48-18-2-8
=30-2-8
=28-8
=20
So, 20 students don't take either of these subjects.
Answer:
20π square units
Step-by-step explanation:
The sector area is found using the proportion ...
sector area / circle area = sector angle / whole circle angle
Multiplying by "circle area", we get ...
sector area = (circle area)( sector angle / whole circle angle)
= (100π)(2/5π)/(2π)
= (100π)(1/5)
sector area = 20π
Answer: 5 weeks
Explanation:
Jess starts with $22 and saves $5 per week, Rosie has $10 and saves $8 per week.
In order to find an equal amount of money between the two girls is by finding a common denominator.
Jess- 22, 27, 32, 37, 42
Rosie- 10, 18, 26, 34, 42
Since we found that they can both end up with $42, after a certain amount of weeks have passed, now you’ll want to count how many numbers are in each row to find the amount of weeks it took to get to an equal amount
Answer:

Step-by-step explanation:
Given

Required
Determine E(119.5)

Simply substitute 119.5 for t

Evaluate the expressions in bracket

Solve 0.5²



Hence;
