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SVEN [57.7K]
2 years ago
8

Paula drops a pebble into the ocean from a 120ft high cliff. Use the formula t=h−−√4 to find how many seconds it takes for the p

ebble to reach the ocean. Round your answer to the nearest tenth of a second.
Mathematics
1 answer:
yaroslaw [1]2 years ago
7 0

Answer:

2.7 seconds

Step-by-step explanation:

We are asked to find how many seconds it takes for an object to fall from a height of 120ft. We will use the given formula, t=h−−√4. Substituting h=120, we find

t=120−−−√4=2.7

So, the pebble reaches the ocean after 2.7 seconds.

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A
SSSSS [86.1K]

Answer: (7 + d) 4 and 4 (7 + d)

Step-by-step explanation:

<em>4 (d + 7) = 4d + 28</em>

<em />

(7 + d) 4 = 28 + 4d (flipped version of 4d + 28)

4 (7 + d) = 28 + 4d (the same)

8 0
2 years ago
Rita car can travel 35 miles on one gallon of gas she needs she needs to trace 157.5 miles how many gallons of gas will she need
Otrada [13]
You would do 157.5/35 to find how much gas she needs

157/35=4.5
She'll need 4.5gallons of gas
3 0
3 years ago
Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the
VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

\lim_{x \to 2} f(x) = 1

\lim_{x \to 2} g(x) = -4

\lim_{x \to 2} h(x) = 0

a) Applying properties of limits

\lim_{x \to 2} f(x) + 5g(x) =  \lim_{x \to 2} f(x) + 5  \lim_{x \to 2} g(x) = 1 + 5*-4 = -19

b) Applying properties of limits

\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64

c) Applying properties of limits

\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1

d) Applying properties of limits

\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16

e) Applying properties of limits

\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0

f) Applying properties of limits

\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0

3 0
3 years ago
the population density of themville is 17.5 thems per acre. Exactly 840 thems live in themville how many acress if themville
postnew [5]
I believe the answer you are looking for is 840 ÷ 17.5 which is 48 acres.
8 0
2 years ago
Please help
katrin2010 [14]
\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}

Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}
7 0
3 years ago
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