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Feliz [49]
4 years ago
5

Explain why -7 has a greater absolute value than the absolute value of 6.​

Mathematics
2 answers:
Stella [2.4K]4 years ago
8 0

Answer:

It's because the absolute value of -7 is 7 and the absolute value of 6 is 6. So, that's why its greater

Anna11 [10]4 years ago
4 0

Answer:

Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative.

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Calculate the length of an arc
jek_recluse [69]
Easy peasy
remember that the arc is a part of the perimiter of the circle aka circumference
also 360 degrees=circle

we are given the radius
calculate circumference
c=2pi times r
r=14
c=pi times 2 itimes 14
c=28pi

100 degrees is the arc

find what fraction of the circumferece thei srepresents
whole=360
100/360=10/36=5/18
so if circumference=28pi then multiply 5/18 by that
5/18 times 28pi=140pi/18=70pi/9
legnth=(70pi)/9 cm
if you were to aprox pi to 3.14 then the answer would be
24.4222222 cm
3 0
4 years ago
may somone give me the answers with question 3 4 and 5. one BRAINLIEST IF SOMONE CAN ANSWER AND FIVE STAR​
Gnoma [55]

Answer:

Well, we need a definition or length/width of the figure of it first, let me see what I can find, I'll leave it in my replies.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles th
PIT_PIT [208]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

6 0
3 years ago
LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE
Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}

\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}

\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}  }

Use the following coordinates from the given diagram:

Point B:  (x₁, y₁) =  (-2, 4)

Point C:  (x₂, y₂) = ( 1,  1 )

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E:  (x₁, y₁) =  (4, 4)

Point F:  (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}

Our calculations show that segment BC and EF have the same slope of -1.  In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.  

Since segments BC and EF have the same slope, then it means that  \displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}.

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1,  1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒  y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒  y = -x + 8.

8 0
3 years ago
Help pls fast and give me the steps<br> -15a-19-35=-84
Nimfa-mama [501]

Answer:

a=2

Step-by-step explanation:

-15a-19-35=-84

-15a-19=-49

-15a=-30

a=2

8 0
3 years ago
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