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2 years ago

14

27/8+11/3 please help

1 answer:

a_sh-v [17]2 years ago

8 0

Answer:

The answer is 7 1/24

Step-by-step explanation:

27/8 + 11/3

I multipled 27/8 by 3/3 (needed the 8 to become 24)

I multiplied 11/3 by 8/8 (needed the 3 to become 24)

We get:

81/24 + 88/24

Then you add

169/24

Simplify

7 1/24

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Solve the absolute value equation |2x + 4| – 3 = -5

Alik [6]

Answer is x=-3, -1. You have two x values because they are broken down into two equations

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3 years ago

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a metalworker has meal alloy that is 15% copper and another alloy that is 60% copper. how many kilograms of each alloy should th

iragen [17]

Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100

L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
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3 years ago

How do I complete these questions a bit confused . (extra credit work )

otez555 [7]

Answer:

(1)

$a = \frac{3\sqrt 3}{2}$

$b = \frac{3}{2}$

(2)

$a = \sqrt 6$

$b = \sqrt 2$

Step-by-step explanation:

Solving (1):

Considering

$\theta = 60^o$

We have:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60^o) = \frac{a}{3}$

Solve for a

$a = 3 * \sin(60^o)$

$\sin(60^o) = \frac{\sqrt 3}{2}$

So:

$a = 3 * \frac{\sqrt 3}{2}$

$a = \frac{3\sqrt 3}{2}$

To solve for b, we make use of Pythagoras theorem

$3^2 = a^2 + b^2$

This gives

$3^2 = (\frac{3\sqrt 3}{2})^2 + b^2$

$9 = \frac{9*3}{4} + b^2$

$9 = \frac{27}{4} + b^2$

Collect like terms

$b^2 = 9 - \frac{27}{4}$

Take LCM and solve

$b^2 = \frac{36 - 27}{4}$

$b^2 = \frac{9}{4}$

Take square roots

$b = \frac{3}{2}$

Solving (2):

Considering

$\theta = 60^o$

We have:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60^o) = \frac{a}{2\sqrt 2}$

Solve for a

$a = 2\sqrt 2 * \sin(60^o)$

$\sin(60^o) = \frac{\sqrt 3}{2}$

So:

$a = 2\sqrt 2 * \frac{\sqrt 3}{2}$

$a = \sqrt 2 * \sqrt 3$

$a = \sqrt 6$

To solve for b, we make use of Pythagoras theorem

$(2\sqrt 2)^2 = a^2 + b^2$

This gives

$(2\sqrt 2)^2 = (\sqrt 6)^2 + b^2$

$8 = 6 + b^2$

Collect like terms

$b^2 = 8 - 6$

$b^2 = 2$

Take square roots

$b = \sqrt 2$

3 0

3 years ago

borishaifa [10]

Answer:

Both triangles have acute angles

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3 years ago

3. A graphic design uses two congruent

FinnZ [79.3K]

A) A (1,-1)

b) P' (3,1)

c) Rule: (x, y) → (x + 2, y - 1)

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3 years ago