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3 years ago

How do you solve this perimeter question? (Image Provided)

Mathematics

1 answer:

Ulleksa [173]3 years ago

5 0

The Circumference of a circle is: 2πr
So the circumference of the circle is 2π(7) = 14π

P = 16 + 16 + 7π + 7π

P = 32 + 14π
P = 75.9822971503
P = 76

So the correct answer is 76.
Hope I helped!

You might be interested in

Due to gravity, objects weigh three times as much on Earth as they do on Mercury.

SpyIntel [72]

Answer:

If an object on Mercury weighed 25lb, it would weigh 75lb on Earth

(25 * 3 = 75)

The answer is b

:")

6 0

3 years ago

(Will dive brainly!! please!!)

Sergio [31]

9514 1404 393

Answer:

A) $157,555

Step-by-step explanation:

The sum of assets is ...

house + 2 cars = $280,000 +5,200 +15,600 = $300,800

The sum of liabilities is ...

mortgage +car loan +credit card +wedding

= $113,545 +9,200 +2,300 +18,200 = $143,245

The family's net worth is the difference between assets and liabilities:

$300,800 -143,245 = $157,555

4 0

3 years ago

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$