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Rufina [12.5K]
3 years ago
14

How do you solve this perimeter question? (Image Provided)

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0
The Circumference of a circle is: 2<span>πr
So the circumference of the circle is 2</span><span>π(7) = 14</span><span>π

</span>P = 16 + 16 + 7π + 7<span>π

P = 32 + 14</span><span>π
P = 75.9822971503
P = 76

So the correct answer is 76.
Hope I helped!</span>
You might be interested in
How many different ways can you write a fraction that has a numerator of 2 as a sum of fractions
Rzqust [24]
At least you can write it as the sum of half of it twice, that is:
2/x = 1/x + 1/x
whatever x number you have, for example:
2/5 = 1/5 + 1/5

But then, you can express a fraction in many different ways, for example again:
2/5 = <span>1/5 + 1/5 = 2/10 + 2/10
</span>= 1/10 + 1/10 + 1/10 + 1/10
so there are an infinite ways of expressing such a fraction.
7 0
3 years ago
What is the result of isolating y2 in the equation below?
lyudmila [28]
STEP-BY-STEP SOLUTION:

( x + 4 )^2 + y^2 = 22

x^2 + 2 × x × 4 + 4^2 + y^2 = 22

x^2 + 8x + 16 + y^2 = 22

y^2 = 22 - x^2 - 8x - 16

y^2 = - x^2 - 8x + 6

FINAL ANSWER:

Therefore, the answer is:

D. y^2 = - x^2 - 8x + 6

Please mark as brainliest if you found this helpful! :)
Thank you <3
6 0
3 years ago
Find the characteristic polynomial of A. Use x for the variable in your polynomial.You do not need to factor your polynomial. A
Vesna [10]

Answer:  The required characteristic polynomial of the given matrix A is x^3+6x+11x+6=0.

Step-by-step explanation:  We are given to find the characteristic polynomial  of the following 3 × 3 matrix A  with unknown variable x :

A=\left[\begin{array}{ccc}0&0&1\\4&-3&4\\-2&0&-3\end{array}\right].

We know that

for any square matrix M, the characteristic polynomial is given by

|M-xI|=0, where I is an identity matrix of same order as M.

Therefore, the characteristic polynomial of matrix A is

|A-xI|=0\\\\\\\Rightarrow \left|\left[\begin{array}{ccc}0&0&1\\4&-3&4\\-2&0&-3\end{array}\right]-x\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]\right|=0\\\\\\\Rightarrow \left|\left[\begin{array}{ccc}-x&0&1\\4&-3-x&4\\-2&0&-3-x\end{array}\right] \right|=0\\\\\\\Rightarrow -x(3+x)^2+1(0-6-2x)=0\\\\\Rightarrow  (x+3)(-3x-x^2-2)=0\\\\\Rightarrow (x+3)(x^2+3x+2)=0\\\\\Rightarrow x^3+6x+11x+6=0.

Thus, the required characteristic polynomial of the given matrix A is x^3+6x+11x+6=0.

6 0
3 years ago
What is x for this problem? i really need help. will offer a lot of points
Umnica [9.8K]

X should equal 52. Sorry if I am wrong.

8 0
3 years ago
Read 2 more answers
Which equivalent is equal to 3(7x-5)
DanielleElmas [232]

Answer:

21x -15

Step-by-step explanation:

use distributive property

a(b+c) = ab+ ac

5 0
3 years ago
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