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gregori [183]
3 years ago
7

What are the factors of 21?

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0
The answer will be 1,3,7
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Solve the equation for a? z=mab. a)a=z+mb b)a=z-mb c)a= mb/z d)a=z/mb
Bingel [31]

Answer:

a = z/mb

Step-by-step explanation:

Given:

\displaystyle \large{z=mab}

To solve for a, divide both sides by the variables mb to isolate a-term.

\displaystyle \large{\dfrac{z}{mb}=\dfrac{mab}{mb}}

Simplify the expression and we finally have solved for a-term.

\displaystyle \large{\dfrac{z}{mb}=a}\\\\\displaystyle \large{a=\dfrac{z}{mb}}

Therefore, the answer to this question is a = z/mb.

Please let me know if you have any questions regarding my answer or explanation!

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2 years ago
I ordered some books online for myself and friends. Each book costs $13 and the store charges a flat rate for shipping of $20. W
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Answer:

13n+20

Step-by-step explanation:

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3 years ago
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Which number should each side of the equation 4/5x=8 be multiplied by to produce the equivalent equation of x = 10?
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3 years ago
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

  • 2 in a unique way (1+1)
  • 3 in two possible ways (1+2, 2+1)
  • 4 in three possible ways
  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

8 0
3 years ago
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