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3 years ago

Let x be toms speed. Solve for x.

Mathematics

1 answer:

Greeley [361]3 years ago

6 0

First cross multiply to get:
80x = 65(x+3) (distribute)
80x=65x+195
15x=195 (subtract 65x from both sides)
x=13 (divide both sides by 15)

Hope this helps

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6x + 5 = 5x + 8 + 2x?

Svetach [21]

Answer:

combine all like terms

6x+5=7x+8

then you get all the x's on one side

-x=3

get x by itself

x=-3

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

¿Cuántas libras de café “La Finca” que se vende a $5 la libra debe mezclarse con 80 libras decafé común que se vende a $2 la lib

Romashka-Z-Leto [24]

Answer:

Necesitamos agregar 40 libras del café La Finca

Step-by-step explanation:

Sea x el número de libras de café de La Finca a mezclar.

Entonces, la cantidad total de libras que obtendremos en la mezcla será (x + 80) libras.

Ahora trabajemos con los precios; Tenemos x libras de La Finca a $ 5 por libra, con 80 libras de café a $ 2 por libra para dar una mezcla de (x + 80) a $ 3 Así, sumaremos el precio de La Finca más la otra variante para llegar al costo de la nueva mezcla.

Matemáticamente;

5 (x) + 2 (80) = 3 (x + 80)

5x + 160 = 3x + 240

5x -3x = 240-160

2x = 80

x = 80/2 x = 40

4 0

3 years ago

Got any 5th grade math, come at me

djyliett [7]

5x(15÷3)=?

What is the answer

8 0

3 years ago

The depth (inches) of water that accumulates in the spring soil from melted snow can be determined by dividing the cumulative wi

nordsb [41]

Let x be the amount of winter snow that accumulates in the spring soil. The equation that represents the situation from the given above is,
x / 12 = w
where w is the depth of water. Substituting the given values,
x / 12 = 6
The value of x from the equation is 72. Therefore, the amount of winter snow is 72 inches. The answer is letter C.

7 0

3 years ago

Read 2 more answers

The true average diameter of ball bearings of a certain type is supposed to be 0.05 in. A one-sample t-test will be carried out

satela [25.4K]

Answer:

a) H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

b) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

c) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

Step-by-step explanation:

Part a

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part b

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part c

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

8 0

3 years ago