What is the shape of the cross section of the figure that is parallel to the triangular bases?
1 answer:
Answer:
a rectangle
Step-by-step explanation:
As we can see that there is a cross-section which we called as a rectangle.
Plus there is a triangle which is to be formed but this would be possible when the plane is perpendicular to the base of the rectangle and at the same time it is parallel to the base of the triangular
Now if a plane cuts a figure i.e parallel to the mentioned base therefore the cross section would be received as a figure which would be parallel to its base
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Answer:
Please see attachment for co troll and treatment for amazon
(side note: your formula C = 2πr^2 is incorrect, it should be C = 2πr)
Answer:
r = 9
Step-by-step explanation:
First let's find the circumference of Circle A. To use the formula we need radius. Since we have a diameter just divide by 2 to get radius. 27 / 2 = 13.5
Now plug that into C = 2πr: 2π*(13.5) = 27π
The question says that the area of circle B is 3x this value, so Circle B's area must be: 27π * 3 = 81π
Now plug that into A = πr^2 and solve for r:
(edited to correct a brain fart)