Answer:
41 minutes before noon
Step-by-step explanation:
The given parameters are;
The time camera A starts taking pictures = 6 AM
The frequency of picture taking by camera A = Once every 11 minutes
The time camera B starts taking pictures = 7 AM
The frequency of picture taking by camera B = Once every 7 minutes
The number of times both cameras take a picture at the same time before noon = 4 times
Let the time the two cameras first take a picture the same time be x, we have;
11·y - 60 = x
7·z = x
Taking the number of times after 7 camera A snaps and noting that the first snap is 6 minutes after 7, we have
11·b + 6 = x
7·z = x
x is a factor of 7 and 11·b + 6 and x is some minutes after 7
By using Excel, to create a series of values for Camera A based, on 11·b + 6, and dividing the results by 7 we have the factors of 7 at;
28, 105, 182, and 259 minutes after 7
Given that there are 60 minutes in one hour, we have;
259/60 = 4 hours 19 minutes, which is 11:19 a.m. or 41 minutes before noon.
