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jeka94
3 years ago
15

Solve the differential equation: dy/dx = 4y2x1/3

Mathematics
1 answer:
labwork [276]3 years ago
4 0
The first thing you should do is use the method of variable separation. Then, integrate both sides to find the solution.
 In this case the answer is
  <span>D. - 1/y = 3x4/3 + C</span> 
 I attach the solution

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Paul needs to buy 5_8pound of peanuts. The scale at the store measures parts of a pound in sixteenths. What measure is equivalen
ryzh [129]

Answer:

10 ÷ 16

Step-by-step explanation:

The computation is shown below

Given that

Paul required to buy 5 by 8 pound of peanuts

And, the scale at the store is in sixteenths

So, the measure that should be equivalent is

Here the denominator should be 16 so it should be multiplied by 2

= 5 ÷ 8 × 2 ÷ 2

= 10 ÷ 16

3 0
2 years ago
A circle has a diameter of 12 inches. What is the area of the circle? А 367 inches squared B 247 inches squared C 127 inches squ
Ann [662]

Answer:

113.1

Step-by-step explanation:

A = πr²

A = π (6)²

A = π (36)

A = 113.09 = 113.1

8 0
2 years ago
A bowl contains 4 red marbles and 3 yellow marbles. Tim randomly draws 3 red marbles from the bowl. He replaces each marble afte
mr Goodwill [35]
So,

The probability of drawing a yellow marble is \frac{3}{7}.
Since he replaces the marble after it is drawn out, the probability of drawing another yellow is the same: \frac{3}{7}.

The probability of drawing a red marble is \frac{4}{7}.

In order to get the probability of drawing 2 yellow marbles and 1 red marble, given that each marble is replaced after it is drawn out, we must multiply the fractions together.

( \frac{3}{7} )( \frac{3}{7} )( \frac{4}{7} ) =  \frac{36}{343}

Because the order of the marbles doesn't matter, we will multiply the probability by 3.
3( \frac{36}{343} ) =  \frac{108}{343}
6 0
3 years ago
Do number 1 plz and thank u
Paladinen [302]
It would be A. R= 50 +10m
8 0
3 years ago
I need answers for this question
Colt1911 [192]

Answer:

1. Use the distributive property to get rid of any parenthesis.

2. Combine like terms

3. Move all variables to one side

4. Inverse operations

8 0
1 year ago
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