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makvit [3.9K]
3 years ago
6

Can someone help me with this :/

Mathematics
1 answer:
slavikrds [6]3 years ago
5 0

Answer:

2x² + x - 1 = 0

a= 2 b= 1 c= -1

x = [ -b +- sqr rt( b^2 -4ac) ] / 2*a

x = -1 +- sqr rt (1 - 4 *2*-1) / 4

x1 = [ -1 + (sqr rt (1 +8)) / 4

x1 = ( -1 + sqr rt (9)) / 4

x1 = (-1 + 3) / 4

x1 = .5

x2 = (-1 -3) / 4

x2 = -4 / 4

x2 = -1

And to check that answer: http://www.1728.org/quadratc.htm

Step-by-step explanation:

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Step-by-step explanation:

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Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2
9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2

\implies \left|0.3-\dfrac{3}{5}k\right|=1.6

<u>Solution 1</u>

\implies 0.3-\dfrac{3}{5}k=1.6

\implies -\dfrac{3}{5}k=1.3

\implies k=-\dfrac{13}{6}

<u>Solution 2</u>

\implies -(0.3-\dfrac{3}{5}k)=1.6

\implies -0.3+\dfrac{3}{5}k=1.6

\implies \dfrac{3}{5}k=1.9

\implies k=\dfrac{19}{6}

<h3><u>Option 2</u></h3>

\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2

\implies \left|0.3-\dfrac{3}{5k}\right|=1.6

<u>Solution 1</u>

\implies 0.3-\dfrac{3}{5k}=1.6

\implies -\dfrac{3}{5k}=1.3

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<u>Solution 2</u>

\implies -(0.3-\dfrac{3}{5k})=1.6

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\implies \dfrac{3}{5k}=1.9

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\implies k=\dfrac{6}{19}

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Step-by-step explanation:

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Read 2 more answers
What is the answer now?
wariber [46]

Answer:

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Step-by-step explanation:

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