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4 years ago

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Chemistry

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ANTONII [103]4 years ago

7 0

1. If the temperature of a gas is increased by 4x, its volume A. will increase by 4x.

2. If the pressure of a gas is decreased by 4x, its volume A. will increase by 4x.

<h3>Explanation:</h3>

The combined gas law combines the three gas laws; Boyle's law, Charles law and Gay Lussac's law together relating pressure, temperature & volume and states thus:

"The ratio of product of Pressure and Volume to that of its Temperature is a constant."

In mathematical terms,

$\frac{PV}{T} =constant\\\\\frac{P_1V_1}{T_1} = k\\\\\frac{P_2V_2}{T_2} = k\\\\\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where P1, V1, T1 are the initial values and P2, V2, T2 the final values.

Therefore,

$V\ \alpha\ T$ .......................................(1)

$P\ \alpha\ \frac{1}{V}$ ......................................(2)

1. If temperature of gas is increased by 4x, keeping pressure constant, from(1) since the volume of gas is directly proportional to its temperature (by Charles' law); it will increase in the same rate as the temperature is increased. Hence, the volume will increase by 4x.

2. If the pressure of a gas is decreased by 4x, keeping temperature constant, from (2), since the pressure of a gas is inversely in proportion to its volume (by Boyles' law), a decrease in pressure leads to increase in volume and vice versa. Hence, the volume will increase by 4x.

irina [24]4 years ago

7 0

Answer:

Explanation:

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