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pychu [463]
3 years ago
13

Which of the following electron configurations for neutral atoms is correct?

Chemistry
2 answers:
geniusboy [140]3 years ago
8 0
Argon: 1s22s22p63s23p6  is right answer,
Serjik [45]3 years ago
6 0

Answer : The correct option is argon.

Explanation :

Neutral atom : It is defined as an atom has equal number of electrons and protons.

  • The given electronic configuration of magnesium is,

1s^22s^22p^63s^23p^6

The atomic number of magnesium is 12 that means it has 12 number of protons and 12 number of electrons.

As per given electronic configuration, there are 18 electrons are present in magnesium which is the electronic configuration of argon. So, this is not a neutral atom.

  • The given electronic configuration of argon is,

1s^22s^22p^63s^23p^6

The atomic number of argon is 18 that means it has 18 number of protons and 18 number of electrons. So, this is a neutral atom.


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Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should as
Sonbull [250]

Answer:

0.100 m AlCl3  will have the highest boiling point

Explanation:

Step 1: Data given

The molal boiling point elevation constant for water is 0.51°C/m

Since those are all  aqueous solutions, the have the same molal boiling point elevation constant

Step 2:

0.100 m C6H12O6

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr = 1

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT = 1 * 0.51 * 0.100

ΔT  = 0.051 °C

0.100 m NaCl

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr =  Na+ + Cl- = 2

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT =2 * 0.51 * 0.100

ΔT = 0.102 °C

0.100 m AlCl3

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr =  Al^3+ + 3Cl- = 4

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT =4 * 0.51 * 0.100

ΔT = 0.204 °C

0.100 m MgCl2

ΔT = i*Kb*m

⇒with ΔT is the boiling point elevation = TO BE DETERMINED

⇒with i = the van't Hoff factr =  Mg^2+ +2Cl- = 3

⇒with Kb = The molal boiling point elevation constant for water is 0.51°C/m

⇒with m = the molality = 0.100m

ΔT =3 * 0.51 * 0.100

ΔT = 0.153 °C

0.100 m AlCl3  will have the highest boiling point

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Explanation:

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