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lubasha [3.4K]
3 years ago
14

Factor 6x + 30 to identify equivalent expressions. Select all that are equivalent expressions.

Mathematics
2 answers:
Tanya [424]3 years ago
5 0

Answer:

6(x+5)

Step-by-step explanation:

lesya [120]3 years ago
4 0
What the person above said. when you multiply 6(x+5) out, you will get 6x+30. you will get the same for all of the other choices except for the 2nd one, but 6(x+5) is the one that is factored out the most, so this would be the best choice. if you need anymore help, let me know!
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What is the difference between y=-2x+3 and the equation in the problem: y = -1.5x + 3?
Ostrovityanka [42]

Answer:

The slope would be different

Step-by-step explanation:

The value by the x is different in both equations while everything else is the same

5 0
2 years ago
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David made $80,950 last year. If his income is decreased by 7.25%, what is his adjusted
Taya2010 [7]

Answer:

75081

Step-by-step explanation: multiply 80950 by 0.9275

5 0
2 years ago
what is the second term in a geometric sequence is 50. the forth term in the same sequence is 112.5 what is the common ratio in
Ulleksa [173]
The common ratio is 1.5 50 * 1.5 = 75, 75 * 1.5 = 112.5 etc.
7 0
3 years ago
HELP WITH THESE QUESTIONS PART 2... 1 Question
Lunna [17]

<u>Step-by-step explanation</u> and Answers:

(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

cos =  \frac{adjacent}{hypotenuse} = \frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{\sqrt{10}}{10}

tan = \frac{opposite}{adjacent} = \frac{3}{1} = 3

csc = \frac{hypotenuse}{opposite} = \frac{\sqrt{10}}{3}

sec = \frac{hypotenuse}{adjacent} = \frac{\sqrt{10}}{1} = \sqrt{10}

cot = \frac{adjacent}{opposite} = \frac{1}{3}

7 0
3 years ago
What is the y intercept of the quadratic function f(x)=x^2+x-6
saveliy_v [14]

Answer:

(0,\, -6).

Step-by-step explanation:

On a cartesian plane, the y-intercept of a function is the point where the graph of that function intersects with the y\!-axis.

The y-axis of a cartesian plane is the same as the equation x = 0 (that is, the collection of all points with an x-coordinate of 0.)

Construct a system of two equations, with one equation representing y-axis and y = f(x) to represent the graph of this function:

\begin{aligned}\begin{cases} y = x^{2} + x - 6 & \text{for the quadratic function} \\ x = 0 & \text{for the $y$-axis}\end{cases}\end{aligned}.

Solve this system for x and for y. If a solution exists, then the y\!-axis and the graph of y = f(x) would indeed intersect. The point (x,\, y) would be the intersection of the y\!\!-axis and the graph of y = f(x)\!.

Substitute the second equation of the system into the first.

\begin{aligned}\begin{cases} x = 0 \\ y = -6\end{cases}\end{aligned}.

Hence, the intersection of the y-axis and the graph of y = f(x) would be (0,\, -6). By definition, this point would be the y\!-intercept of y = f(x)\!.

4 0
2 years ago
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