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kotykmax [81]
3 years ago
5

Thx for helping me cheat on test

Mathematics
2 answers:
zimovet [89]3 years ago
7 0

Answer:

any

Step-by-step explanation:

time buddy ol pal lamabndkemnsha

NemiM [27]3 years ago
5 0

Answer:

lol same I do it all the time....

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Seven less than twice a number is 5
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Yes, i believe so because u can count back twice and u will get 5. You could al so do: 7-2=5. Hope this helps
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5c squared- d squared+3/2c - 4d...c= -1. d= -4​
riadik2000 [5.3K]

For this case we have the following expression:

5c ^ 2-d ^ 2 + \frac {3} {2} c-4d

We must find the value of the expression when:

c = -1\\d = -4

Substituting we have:

5 (-1) ^ 2 - (- 4) ^ 2 + \frac {3} {2} (- 1) -4 (-4) =\\5 (1) -16- \frac {3} {2} + 16 =\\5-16- \frac {3} {2} + 16 =\\-11- \frac {3} {2} + 16 =\\- \frac {25} {2} + 16 =\\\frac {-25 + 32} {2} =\\\frac {7} {2}

Finally, the value of the expression is:

\frac {7} {2}

ANswer:

\frac {7} {2}

5 0
4 years ago
What is the explicit formula for this sequence?<br> -9, -3, 3, 9, 15, ...
jok3333 [9.3K]

Answer:

What is the explicit formula for this sequence? -9, -3, 3, 9, 15, ... - did not match any news results.

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8 0
3 years ago
Collin Buys a TV for £720 depreciate at a rate of 4% per year how much will it be worth in three years
belka [17]

Answer:

The worth of the TV after 3 years is £809.90208

Step-by-step explanation:

The answer to given question can be found from the anual depreciation formula and solving for the Future Value (F. V.) of the machine

The given parameters of the TV are;

The amount at which Collin buys the TV, P = £720

The rate at which the TV depreciates at, R = 4%

The number of years the depreciation is applied, T = 3 years

The amount the TV is worth after three years, 'A', is given as follows;

A = P \cdot \left(1 + \dfrac{R}{100} \right )^T

By plugging in the known values, we have;

A = 720 \cdot \left(1 + \dfrac{4}{100} \right )^3 = 809.90208

The amount the TV is worth after three years, A = £809.90208

8 0
3 years ago
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