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3 years ago

Write the time another way 23 minutes after 4

Mathematics

2 answers:

12345 [234]3 years ago

8 0

4:23

Would be the answer

Maslowich3 years ago

3 0

23 minutes after 4 o'clock is the same as 4:23.

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At 2:00 p.m. two cars start toward each other from towns that are 240 miles apart. The rate of one car is 15 mph faster than the

Vesnalui [34]

Hello! :)

The <u>answer</u> is x+15!

~Hope it helps!~ :)

3 0

3 years ago

In a recent year, 27.9% of all registered doctors were female. If there were 53,700 female registered doctors that year, what wa

Elis [28]

Answer:

The total number of registered doctors was 192,473.

Step-by-step explanation:

This question can be solved using a rule of three.

53700 is 27.9% = 0.279. The total number of registered doctors is x, which is 100% = 1. So

53700 doctors - 0.279

x doctors - 1

$0.279x = 53700$

$x = \frac{53700}{0.279}$

$x = 192473.11$

Rounding to the nearest whole number.

The total number of registered doctors was 192,473.

5 0

3 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8?

zmey [24]

2x² + 3x -8 = 0

a = 2 , b = 3 , c = -8
So..
D = b²-4ac = 9 + 64 = 73

for bigger solution , use x = -b + √D / 2a
For smaller solution, use x = -b - √D / 2a

So
= -3 + √73 / 2. 2
= 1/4 (√73 -3)

Hopefully helpfull.. ^_^

8 0

4 years ago

Read 2 more answers

If the nth term of an AP is (7-4n) then its common difference is

Hitman42 [59]

Given nth term of an AP = 7-4n

Put n = 1 then t1 = 7-4(1) = 7-4 = 3

Put n = 2 then t2 =7-4(2) = 7-8 = -1

Common difference = t2-t1 = -1-3 = -4

3 0

3 years ago

Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

6 0

3 years ago