The value of x from the given equation is -4/3
<h3>Factorization</h3>
Given the quadratic equation x^2 – 3x – 4 = x^2 – 6x + 8
x^2 – 3x – 4 - x^2 + 6x - 8 = 0
-3x + 6x - 4 + 8 = 0
3x + 4 = 0
- Subtrcat 4 from both sides
3x + 4 - 4 = 0 - 4
3x = -4
3x/3 = -4/3
x = -4/3
Hence the value of x from the given equation is -4/3
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This is = 4 therefore no property is applied
Answer:
x=2,1 solving with quadratic formula
Step-by-step explanation:
Answer:
Step-by-step explanation:
If you meant f(x) = √x - 1, then the domain is [0, infinity).
If you meant f(x) = √(x-1), then the domain is [1, infinity).
When any ambiguity may rear its ugly head, use parentheses, as indicated here.
Answer:
Step-by-step explanation:
{y = 6x − 11
{y = x² + 4x − 10
x² + 4x − 10 = 6x − 11
- [6x − 11] - [6x − 11]
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x² - 2x + 1
![{[x - 1]}^{2} = 0](https://tex.z-dn.net/?f=%7B%5Bx%20-%201%5D%7D%5E%7B2%7D%20%3D%200)
1 = x [Plug this back into both equations above to get the y-coordinate of −5]; −5 = y
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