What is the most reasonable answer for PI squared?
1 answer:
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Answer:
The domain is {x : x ∈ R} , the range is {y : y > 0}
Step-by-step explanation:
* Lets explain how to solve the problem
- The general form of the continuous exponential function is
where a is the initial value and k is the growth factor
- We have some ordered pairs from the continuous exponential
function
- The ordered pairs are:
(0 , 4) , (1 , 5) , (2 , 6.25) , (3 , 7.8125)
- Lets substitute the values of x and y in the equation to find a ,
∵
∵ x = 0 and y = 4 ⇒ 1st ordered pair
- Substitute x and y in the equation
∴
∴
- The value of = 1
∴ a = 4
- Substitute the value of a in the equation
∴
∵ x = 1 and y = 5 ⇒ 1st ordered pair
- Substitute x and y in the equation
∴
∴
- Divide both sides by 4
∴ = 1.25
- Substitute the value of in the equation
∴
- The domain of the function is all the values of x which make the
function defines
- The range is the values of y corresponding to x
∵ There is no value of x makes the function undefined
∴ <u><em>The domain is all real numbers</em></u>
∵ y never takes a negative value
∴ <u><em>The range is all the real positive numbers</em></u>
* <em>The domain is {x : x ∈ R} , the range is {y : y > 0}</em>
Answer:
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Step-by-step explanation:
The null hypothesis is:
The alternate hypotesis is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.
This means that
Assume the population standard deviation is 6.2 weeks.
This means that
Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
We have to find the pvalue of Z, looking at the z-table, when . It if is lower than 0.05, it provides evidence.
has a pvalue of 0.0113 < 0.05.
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance