Answer:
x = -2
∠A = 35
Step-by-step explanation:
x + 37 + x + 57 = 90
reduce:
2x = -4
x = -2
∠A = 37-2 = 35
Answer:
I'm pretty sure it's (0,1)
Answer:
The equation for nth term is 3n + 5.
Step-by-step explanation:
Let a1 be a,
a3 = a + (n - 1)d
or, 14 = a + (3 - 1)d
so, 14 = a + 2d
Now,
a5 = a + (n - 1)d
or, 20 = a + (5 - 1)d
or, 20 = a + 4d
now,
a + 4d = 20
a + 2d = 14
now,
a + 4d - ( a + 2d) = 20 - 14
or, a + 4d - a - 2d = 6
or, 2d = 6
so, d = 3
Now,
a + 2d = 14
or, a + 2(3) = 14
or, a = 14 - 6
so, a = 8
Now,
an = a + (n - 1)d
or, an = 8 + (n - 1)3
or, an = 8 + 3n - 3
so, an = 3n + 5
Recall the formula for finding the area of a rectangle:
Area = Length × Width
Recall the formula for finding the perimeter of a rectangle:
Perimeter = 2 ( Length + Width )
Given in your problem:
Area = 40 sq. units
Perimeter = 26 units
Required to solve for:
Length (L) and width (W)
• First, substitute the given to the formula:
Area = Length x Width
40 = L × W ⇒ equation number 1
Perimeter = 2 ( Length + Width )
26 = 2 ( L + W ) ⇒ equation number 2
• Simplifying equation number 2,
13 = L + W
• Rearranging the equation,
L = 13 - W ⇒ equation 3
Substituting equation 3 from equation 1:
( equation 1 ) 40 = (L)(W)
( equation 3 ) L = 13 - W
40 = (13 - W) (W)
40 = 13W - W²
( regrouping ) W² - 13W + 40 = 0
( factoring ) (W - 8) (W - 5) = 0
W - 8 = 0 ; W - 5 = 0
W = 8 ; W = 5
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.
• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.
(equation 3) L = 13 - W
for W = 8 ⇒ L = 13 - 8
L = 5 units
for W = 5 ⇒ L = 13 - 5
L = 8 units
<span>The table must show:
Time (minutes) number of gallons remaining
X y
0 Yo
1 Yo – 1.5
2 Yo – 2*1.5
3 Yo – 3*1.5
4 Yo – 4*1.5
And the equation will be ; Y = Yo – 1.5 x, where Yo is the initial amount of water in the bathtub.</span>
