Centre of the circle (-6,-4) and radius =6 units :)
Answer:
2222222
Step-by-step explanation:
Answer:
Scale Factor - Finding Sides. L1S1. 3) Scale factor of S to T is 4 : 1. ; x = y = 4) Scale factor of G to H is 1 : 7. ; x = y = 20 yd. 10 yd. S. T.
Step-by-step explanation:
<em> A scale factor in math is the ratio between corresponding measurements of an object and a representation of that object. If the scale factor is a whole number, the copy will be larger. If the scale factor is a fraction, the copy will be smaller.</em>
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<em>Hope this helps:) Have a great day! </em>
<em>Brainliest?</em>
The first false statement in the proof as it stands is in Line 5, where it is claimed that a line of length 2.83 is congruent to a line of length 4.47. This mistake cannot be corrected by adding lines to the proof.
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The first erroneous tactical move is in Line 4, where the length of DE is computed, rather than the length of FD. This mistake can be corrected by adding lines to the proof.
A correct SAS proof would use segment FD in Line 4, so it could be argued that the first mistake is there.
9514 1404 393
Answer:
(a) one parallelogram
(b) opposite sides are 3 inches and 4 inches. Opposite angles are 45° and 135°
(c) yes, all side lengths can be determined, see (b)
Step-by-step explanation:
Opposite sides of a parallelogram are the same length, so if one side is 3 inches, so is the opposite side. Similarly, if one side is 4 inches, so is the opposite side. If sides have different lengths, they must be adjacent sides. The given numbers tell us the lengths of all of the sides.
The 4 inch sides are adjacent to the 3 inch sides. Thus the angle between a 4 inch side and a 3 inch side must be 45°. Opposite angles are congruent, and adjacent angles are supplementary, so specifying one angle specifies them all.
Only one parallelogram can be formed with these sides and angles. (The acute angle can be at the left end or the right end of the long side. This gives rise to two possible congruent orientations of the parallelogram. Because these are congruent, we claim only one parallelogram is possible. Each is a reflection of the other.)