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Ira Lisetskai [31]

2 years ago

7

Jenny's frog made one jump of 2.34 m. Christina's frog made jumps of 1.22 m and 0.89 m. How much further did Jenny's frog jump i

n one jump than Christina's frog in two jumps combined? A. 0.23 B. 0.33. C. 1.12. D. 1.45

1 answer:

Alinara [238K]2 years ago

7 0

The answer is A, i hope that i helped

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Simplify the expression 4(2x - 3y) ASAP

uranmaximum [27]

Answer:

8x - 12y

Step-by-step explanation:

4(2x-3y)

Distribute/multiply the 4 to everything in the parentheses

4 * 2x = 8x 4 * -3y = -12y

8x - 12y

4 0

3 years ago

Read 2 more answers

Simplify the complex fraction.

lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}$

Step 2: Simplify the denominator

$$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}$

Step 3: Using step 1 and step 2

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}$

Step 4: Using fraction rule:

$$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}$

$$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}$

Cancel the common factor r and t², we get

$$=\frac{64 r^{2} \cdot 9 }{16 \cdot 15 t^2 }$

Cancel the common factors 16 and 3 on both numerator and denominator.

$$=\frac{4 r^{2} \cdot 3 }{ 5 t^2 }$

$$=\frac{12 r^{2} }{ 5 t^2 }$

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2} }{ 5 t^2 }$

The simplified fraction is $\frac{12 r^{2} }{ 5 t^2 }$ .

5 0

3 years ago

-1/2m=-9 what does m=

lilavasa [31]

Answer:

m = 18

Step-by-step explanation:

Step 1: Write out equation

-1/2m = -9

Step 2: Multiply both sides by -2

m = 18

5 0

3 years ago

1. What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4), and D(5,2)?

zaharov [31]

The first one is B because of the first attachment. The second one is A because of the second attachment. The third one is C because of the expression used to solve for sum of angles:
(n-2)180
(8-2)180
1080
Hope this helps!

7 0

2 years ago

Read 2 more answers

1 The legs of a triangle are 6 cm and 8 cm. The hypotenuse is 14 cm. Is it a right triangle?

Vitek1552 [10]

Answer:

this is not a right triangle

Step-by-step explanation:

^ = squared

The formula forthe Pythagorean theorem is a^+ b^ = c^

If this is a right triangle this must be true

6^ + 8^ = 14^

36 + 64 = 196

100 is not equal to 196

So this is not a right triangle

3 0

3 years ago